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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Mar 2008 15:25:19 IST
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prove that if a plane has the intercepts a,b,c and is a t a distance p units from origin, then 1/a^2 + 1/b^2 + 1/c^2 =1/p^2
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17 Mar 2008 15:29:08 IST
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The equation of the plane is: x/a+y/b+z/c =1 so distance from (0,0,0) is: p=1/root(1/a^2 + 1/b^2 +1/c^2) and so rearranging you get the answer.
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