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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Jun 2008 18:20:01 IST
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two cities A and B are connected by a regular bus service with busses playing in either direction every t sec.The speed of each bus is uniform and equal to Vb. A cyclist cycles from A to B with a uniform speed of Vc. a bus goes past the cycle in T1 sec in the direction A to B and every T2 sec in the direction B to A. Then T1 and T2 are respectively
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15 Jun 2008 18:21:59 IST
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please reply.
rate is assured with a salute
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15 Jun 2008 18:23:50 IST
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hey rudra,dee dee,chimanshu..............
please reply
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16 Jun 2008 20:02:58 IST
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T1 = Vbt/( Vc-Vb )
T2= Vbt /( Vc+Vb )
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16 Jun 2008 21:55:41 IST
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yarrr
ur t2 is right but t1 is wrong.
t1 is Vbt/(Vb-Vc).
i am rating u becoz u r very near to the ans.
but main point is that
HOW U DO IT????????????
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ok have alook at this
if you are a stationary person standing on the road A to B a bus will pass you in every t sec. so distance travelled by the bus1 before bus2 arrives is Vbt. now you start cycling from A to B and so you have a velocity Vc in the direction from A to B. so busses travelling from A to B will seem to move slower to youi.e they will have a relative velocity of Vb-Vc and hence the same distance Vbt for the cyclist will be covered in T1=Vbt/Vb-Vc
for the bus commin in the opposite direction Bt to A it will seem to come faster with a relative velocity of Vb+Vc and so that same distance for the cyclist will be covered in T2=Vbt/Vb+Vc
this question is all about relative velocity and vectors
correct me if i am wrong or nudge me if you have any doubts
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16 Jun 2008 22:39:38 IST
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thnx
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20 Jun 2008 20:33:05 IST
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U should mention , whether Vb >Vc or Vc>Vb ,
( of course practically Vb>Vc which I overlooked )
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