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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 12:14:07 IST
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Find |a-b| if |a|=2 |b|=3 a.b=4
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19 Mar 2008 12:15:52 IST
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2x3xcosA=4
cosA=2/3
so we have
|a-b|=root(4+9-2*2*3*2/3)
=root(13-8)=root5
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19 Mar 2008 12:16:15 IST
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this is simple enough
cos ? = 2/3
then mod (a-b) = sqrt. (a2+b2 -2ab cos ? )
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all the best ... |
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19 Mar 2008 14:16:08 IST
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| a-b |2 =(a-b).(a-b)
=a.a-a.b-b.a+b.b
=|a|2 +|b|2 -2a.b
=4+9-8
=5
|a-b|= 5
..............
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19 Mar 2008 14:18:32 IST
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|a-b|=sqrt(|a|2+|b|2-2(a.b))
=sqrt(4+9-8)
=sqrt(5).
Please rate me.
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ANAND KRISHNAN |
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