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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jul 2008 20:52:35 IST
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the area of parallelogram formed wih vectors a=^i-2^j and b=3^i-2^j as adjacent sides is
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jul 2008 20:58:31 IST
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Area of parellelogram formed by vectors A and B as adjacent sides =
|A x B| (cross product)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jul 2008 21:02:29 IST
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AREA OF PARALLELOGRAM = | A x B |
substitute the values in place of A and B
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jul 2008 07:03:51 IST
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substituting the above formula we get | i j k | | 1 -2 0 | | 3 -2 0| = 4 k and magnitude is 4 sq units`
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sathya prabha girish |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jul 2008 09:37:50 IST
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Thats right
Area of parallelogram is = I A X BI
Here A=i-2j and B=3i-2j
i j k
Thus area = 1 -2 0
3 -2 0
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Jul 2008 08:22:57 IST
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ar5ea of the paralellogram= base *height.=a.bsin = =4UNITS
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