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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2007 20:26:14 IST
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The position vector of a point P is r=xi+yj+zk where x belongs to N,y belongs to N,z belongs to N and a=pi+qj+sk.If r.a<=10,then what is the number of possible positions of P ?NOTE:-Their is an arrow over r and a each and i,,j,k are associated with caps as usual.
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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24 Apr 2007 22:39:31 IST
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what about p, q and s????? are they natural numbers, or integers????
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Manasi....
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27 Apr 2007 21:06:40 IST
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Well you are going correct.Consider both the cases.Firstly,take p,q,s as natural numbers and then take them as integers.But certainly not rationals.
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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2 May 2007 17:02:52 IST
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so u want number of positive integral solutions of p+q+r=10 so gi ve one value for each u get p+q+ v =7 use multinomial theorem, (n+r -1)Cr where n=3 and r=7 _
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25 May 2007 11:23:56 IST
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Good question.....
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26 May 2007 16:05:43 IST
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use multi nomial theorem if not clear ask me
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daring indian |
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14 Jun 2007 15:12:11 IST
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yup use multinomial theorem and sum ans is 110
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devesh
La parada de tettas |
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