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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: vector challange:
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abhishek_varshney (295)

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A article acted on by the constant forces 4i+j-3k and 3i+j-k is dislaced from point  i+2j+3k to the point 5i+4j+k. then what is the total workdone?????????????????????

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akhil_o (2709)

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F total= 7i+2j-4k
displacement=r2-r1= 4i+2j-2k

Work done= F.x
=28+4+8
=40

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raulrag009 (1223)

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Simple\; one\\\\
Let\;F_1=4i+j-3k\\
       F_2=3i+j-k\\\\
Net\;Force\;on\;the\;article\;is\\
F_{net}=F_1+F_2=7i+2j-4k\\\\
Displacement\;d=4i+2j-2k\\\\
Work\;Done=F_{net}.d\\
\quad=(7i+2j-4k).(4i+2j-2k)=28+4+8=40N
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