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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Vector product
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m.viddya (101)

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Q.pa' is a vector perpendicular to i' and j' whose magnitude is 2 where 'p' is  a scalar then
1.a'=k' and mod a'=p
2.a'=2/pk' and mod a'=2/p
3.a'=2pk' and mod a'=2p
4.a'=pk' and mod a'=p/2
 
    
BALGANESH (682)

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ans is (c), becauce since  a is perpendicular to i, j it would be in the direction of k, where k is unit vector  and the value of  p = 1, since  a has magnitude is 2 ,so mod of a = 2p, in all other options both (the vector a and its mod are not having the same magnitude )
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Greatdreams (3282)

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I too think answer is c

You can obtain them by eliminating the other ones.Balganesh is  correct i  think.


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chetan_kp (297)

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hey i hve a small doubt coz ifeel the ans shd be 2nd option
mod pa' = 2
hence mod a' = 2/p

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m.viddya (101)

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well...the answer is the 2nd option..can someone give the explantion plz....
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saurabhpanda (36)

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perhaps u r getting confused. in 2nd opt. k' is in num and not dinominator.
now i think quest. is done...
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nikita19 (30)

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pa'=tk'
given that |pa'|=2
p|a'|=2
|a'|=2/p
hence the second option is correct
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