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If a rigid body is rotating about an axis passing through the point 2i-j-k and parallel through the points i-2j+2k with an angular velocity 3 rad/sec , then find the velocity of the point of the rigid body whose position vector is 2i+3j-4k
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the axis would be the direction of w
and r can be find out by subtracting (point on boudary-parallel point)
Now w can be given in vector form and v can be given in vector form using
v=w(cross)r/(mod(r))^2
put v as Vxi+Vyj+Vzk