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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2007 19:43:13 IST
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Q] If "a" vector and "b" vector are unit vectors at right angle then a unit vector which is equally inclined with each "a"vector, "b" vector and "a cross b" vector is 1](1/2)1/2( a+b) 2](1/2)1/2( a-b) 3](1/3)1/2( a+b+ "a cross b") 4](1/3)1/2( a+b-"a cross b")
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IF U THINK U CAN, U CAN........IF U THINK U CAN'T, U CAN'T.........
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THEN U WILL SUCCEED FOR SURE!!!
     
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2007 19:53:08 IST
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it is : A
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2007 20:05:23 IST
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The answer is 3](1/3)^1/2 ( a+b+ "a cross b")
IF CORRECT, PLEASE RATE...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2007 20:09:50 IST
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aysh ur right...........could u plz explain the steps plz? then i will definitely rate u...........plz explain the steps........
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IF U THINK U CAN, U CAN........IF U THINK U CAN'T, U CAN'T.........
BE THE BEST OF WHAT EVER YOU ARE!!!
THEN U WILL SUCCEED FOR SURE!!!
     
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2007 20:22:25 IST
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Hi Kartik,
SHORTCUT AGAIN>> Take a=i ,b=j, a x b=k
THAT'S IT PLEASE RATE...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2007 17:42:46 IST
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the vector equally inclined with both, will be the angle-bisector of the angle b/w the two vectors,,,, so from the figure the required vector will be k ( a + b) whr bold a and b represents the unit vectors a and b, nd k is the length of the required vector as a and b will form a rectangle thrfore its diagonal = sqrrt (a^2 + b^2) = sqrt 2
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