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Remeber that a few bond angles can be calculated by the formula --
@ = cos(inverse)(1/p) where p indicates the no of p orbitals taking part in the hybridization.
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If charges on them are widely different--
Yes they will attract each other because the charge on one is much much larger than the smaller charge thus if they are brought closer then due to induction -ve charge comes up and attraction occurs.
But if you say there is only size difference it seems a bit awkward.
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H2O2 can be used as both an oxidizing as well as a reducing agent and in most organic reactions the H2O2 plays the role of organic peroxide.Ir forms free radicals as 2OH*.
On the other hand HBr is mainly the reagent tsking part in ene / ynes
It gives free rad in hv and also gives addition reactions.
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bond angle @ = cos(inverse) (1/p) where p represents the no of p orbitals engaged in hybridization
Mostly the values are true if the dipole moments are not affecting.
Ex---sp ----cos(inverse) (1) =180
sp2 ------cos(inverse)(1/2) = 60
sp3-------cos(inverse)(1/3) =109.47 etc.
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When they form a square then both diagonals are equal
B(x,y)
D(x,-y)
A(0,0)
C(2x,0)
l =( x^2 + y^2)^1/2
Differentiating dt
0 = 1/2(2x dx/dt + 2y dy/dt)
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( x^2 + y^2)^1/2
2x dx/dt + 2y dy/dt = 0
When they form a square
x= l /(-/2)
y= l /(-/2)
dx / dt =v
dy / dt =-dx / dt =v (d) Ans
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For molality ---
100 ml of each sol
--> 121.8 gm 30% sol ----121.8 X 70/100 =85.3 gm solvent and 121.8 - 85.3 gm solute =36.5 gm solute = 0.37 mol acid
Similarly
---> 161 gm 70% sol ----161 X 30/100=48.3gm solvent and
161-48.3 =112.7 gm acid =1.15 mol acid
Thus on mixing 100 ml of each solution of 200 ml forms with
1.15 +0.37 =1.52 mol acid
Total mass of solvent = 85.3 + 48.3=133.6 gm
Molality =1.52 / 0.1336 = 11.4 m Ans
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30 % acid d=1.218
30 gm acid ------ 100 gm solution------70 gm solvent
30/98 mol=0.31 mol acid ---100 gm sol
0.31 mol acid in 100/1.218 ml =82.1 ml solution
M1=0.31 x1000/82.1 = 3.8 M
Similarly-
70 % acid d=1.61
70 gm acid ------ 100 gm solution-------30 gm solvent
70/98 mol=0.71 mol acid ---100 gm sol
0.71 mol acid in 100/1.218 ml =62.1 ml solution
M2 =0.71 x 1000/62.1 =11.4 M
Molarity of Mixture =M1V + M2V / 2V = (M1 +M2 )/ 2
=11.4+3.8/2 = 7.6 M ans
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1- Mol Wt. =158
100 gm sol ----5 gm solute
100 gm sol----5/158 mol =0.032 mol of solute
Mass of solvent = 100 -5= 95 gm
Molality=0.032/0.095 = 0.34 m Ans
Vol of soln = 100/1.04=96.2 ml
Molarity = 0.032/0.0962 = 0.33 M Ans
Mol of water = 95/18 =5.3 mol
Mol of solute = 0.032
Mol Fraction = 0.032 / 5.332 = 6 x 10 ^-3 Ans
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I think the third one is the most basic
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since cot( ) is 1 or more than 1 thus here it should be exactly one in this case because elsewise the product cannot be 1
Thus A1=A2=A3=...................An=45
cos(45) = 1/ -/ 2
Thus the product = (1/ -/ 2 )^n Ans
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Have you ever come across a question based on decreasing acceleration Buddy Guy but you may have come across many questions on decelaration where acc was constant.I think what you say is wrong.
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6 particles are located at the 6 corners of a regular hexagon of side a. If each moves with a constant velocity of v always towards the particle at the next corner then find the time taken for the particles to meet. (ANS= 2a/v) Answer first and get the salute.
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I think the answer should be (A) because HCl(gas) will evolve out but HBr being a liquid remains in the solution and decomposes on heating.
Actually I am not sure enough yet.
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1-Check for the inductive effects if any . Any-I group will increase the strength of the acid.
2-Check whether the acid after losing its hydrogen ion is stable.More stable its anion the more strong will be the acid.
3-If the molecule of the acid is more stable then it will have lesser tendancy to lose the H+ ion.
4-Remember that the +I groups will decrease the acid strength.
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Short Cut Trick----
C0 Cr + C1Cr+1+ ............... ........... = (2n)!
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(n-r)! X (n+r)!
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Thank You Ma'am that was an excellent experience for me to talk to you.
Thank You once again.
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I read somwhere that such assumptions are made in honour of the ancient scientists and their works
Also for simplicity as most of the cases considered all on the earth
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SORRY THE FORMATTING IS WRONG
Monovalent Divalent Trivalent Tetravalent etc.
-yl -Diyl - Triyl -tetrayl
-Ylidene -Ylidyne -Ylylidyne etc.
-Ylylidene -Diylidene
-Diylylidene
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Monovalent Divalent Trivalent Tetravalent etc.
-yl -Diyl -Triyl -tetrayl
-Ylidene -Ylidyne -Ylylidyne etc.
-Ylylidene -Diylidene
-Diylylidene
This is directly from an IUPAC document.
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Thogh I could not find the answer by trigo----
But on simplification I got --
= 2
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cos45 + sin 25
since for small angle(rad) sin x =x
Thus sin 25 =25xpi/180 = 0.436
Thus =2/(0.707+0.436)
=1.75
=(nearly) (3)^1/2 Ans
We can use this in case if we need this simplification in physics etc but not in Maths
Still trying to solve it.
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