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Catalogs Discussion Forums -> Mechanics -> Best AIEEE Question -> Go to message
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q-When an elastic material with Young's modulus Y is subjected to a streching stress S, the elastic energy stored per unit volume of the material is; [ans- S^2/2Y
 
       please give detail answer
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q-If a wire is streched by hanging a weight from its end,the elastic potential energy per unit volume in terms of the longitudinal strain  and modulus of elasticity  Y is? [ans-(Y^2)/2
       
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1. The hybridization state of C atom in butendioic acid is :
2 3
(1) sp   (2) sp   (3) both two  (4) sp
 
2.  Which of the following is not a isomer of pentane :
(1) n-pentane
(2) 2, 2-dimethy 1 propane
(3) 2, 3-dimethy 1 butane 
(4) 2-methy 1 butane
 
3. The oxidation number of C atom in Ch CI  and CCI  are respectiv
2 2 4
(1) -2 and ? 4  (2) 0 and ? 4 (3) 0 and 4 (4) 2 and 4
 
4. Which of the following dissolves in lonic solvents :
(1) C H  (2) CH OH (3) CCI  (4) C H 
6 5 3 4 5 12
 
5. The conjugate acid of HS is :
-2
(1) S  (2) H S  (3) both two  (4) none
2 2
 
6. Phenolphthalein of pH range [8-10] is used in which of the followin
titration as a suitable indicator :
OH and HCI
(1) NH
4
(2) NH
OH and HCOOH
4
(3) NH OH and C H O 
4 2 4 2
(4) NaOH and C
O H 
2 4 2
 
7. Which of the following is iron are :
(1) Malachite  (2) Hernatite (3) Siderite  (4) Limonite
 
8. The molar concentration of chloride ions in the resulting solution o
 will be :
ml.of 3.0 M NaCI and 200 ml. of 4.0 M BaCl
2
(1) 1.7 M (2) 1.8 M (3) 5.0 M (4) 3.5 M
 
9. Which of the following has least bond energy :
-2 - +
 (2) N   (3) N   (4) N 
(1) N
2 2 2 2
 
10. Which of the following species has highest bond energy :
-2 + -
(1) O  (2) O   (3) O  (4) O 
2 2 2 2
 
11. Which of the following compound is not aromatic :
(1) 1, 3-cyclobutene 
(2) pyridine
(3) furane
(4) thiophene
12. Which of the following compound is used as refrigerant :
(1) CCI F 
2 2
(2) CCI
 
4
(3) CF 
4
(4) Acetone
 
13. Which of the following is weak acid :
(1) C H  (2) CH -C=CH (3) CH =CH    (4) CH -C=C-CH 
6 6 3 2 2 3 3
 
14. L.P.G. mainly consist of the following :
(1) Methane (2) Hydrogen  (3) Acetylene  (4) Butane
 
-9
15. The solubility product of CaCo  is 5 x 10 . The solubility will be :
3
-5 -5 -4 -9
(1) 2.5 x 10   (2) 7 x 10  (3) 2.5 x 10   (4) 2.2 x 10 
 
16. The outer electronic configuration of alkali earth metals is :
10 1 6
(1) nd
 (2) ns   (3) np   (4) ns 
2
 
17. The nature of 2, 4, 6-trinitrophenol is :
(1) Neutral (2) Basic (3) Acidic (4) Weak basic
 
18. Which of the following group is sharp ortho and para directive :
(1) ?C H  (2)-OH  (3) ?CH  (4) ?CI
6 5 3
 
19. By which of the following process hydrocarbons are found from petroleum :
(1) combustion
(2) fractional distillation
(3) addition
(4) all above
 
20. A sample of petroleum contains 30% n-heptane, 10% 2-methyl hexane and
60% 2, 2, 4-trimethyl pentane, the octane no. of this sample will be :
(1) 30% (2) 60% (3) 10% (4) 70%
 21. In which of the following halogens p-electrons does not take part in
resonance :
(1) CH
=CH-CH Cl  (2) BrC H 
2 2 6 5
H Cl   (4) CH =CHCl
(3) C
6 5 2
22. Which of the following statement is false :
(1) 40% solution HCHO is known as formalin
(2) HCHO is least reactive in its homologous series
(3) The B.P. of isovarelaldehyde is less than n-varelaldehyde
(4) The boiling point of ketones are higher than that of aldehydes
23. If n + ?? = 8 then the expected no. of orbitals will be :
??
(1) 4  (2) 9  (3) 16  (4) 25
Alc. KOH        2Cl             Ca(OH)
             
2 2
24. A              B             C                   here the compound C will be :
(1) Lewsite (2) Westron (3) Acetylene tetra chloride (4) Both 2 and 3
 
25. Which of the following is least hydrolysed :
(1) BeCl  (2) MgCl  (3) CaCl  (3) BaCl 
2 2 2 2
 
26. The laughing gas is :
O  (2) NO  (3) N O (4) N O 
(1) N
2 4 2 2 5
 
-6
27. The hydrogen ion concentration of a solution is 3.98 x 10  mole per liter. The
pH value of this solution will be :
(1) 6.0  (2) 5.8  (3) 5.4  (4) 5.9
 
28. The reaction of sodium acetate and sodalime gives :
(1) Butane (2) Ethane (3) Methane (4) Propane
 
29. Which of the following acids does not contain ? COOH group :
(1) Carbamic acid (2) Barbituric acid 
(3) Lactic acid  (4) succinnic acid
 
30. Which of the following compound of xenone does not exists :
(1) XeF  (2) XeF  (4) XeF  (4) XeF 
6 4 5 2
 
31. FeSO
, 7H O is :
4 2
(1) Mohr?s salt     (2) Blue vitriol (3) Green vitriol  (4) White vitriol 
 32. The solution of BiCl3 in dil. HCI when diluted with water white preci
formed which is :
(1) Bismith oxychloride (2) Bismith oxide
(3) Bismith hydroxide  (3) none of these
33. The strongest acid is :
(1) acetic acid
(2) trichloroacetic acid
(3) dichloracetic acid
(4) monochloroacetic acid
34. The false statement regarding alkane is :
(1) This does not perform polymerization reaction
(2) This does not gives elimination reaction
(3) It does not disappear the colour of dilute KMnO
 solution

(4) It does not decolourise bromine water
35. Which of the following is strongest base :
(1) C H NH   (2) CH NH 
 
36. Which of the following aromatic compound gives sulphonation reaction very
easily :
(1)  Chlorobenzene  (2) Nitrobenzene (3) Toluene (4) benzene
 
 
37. The geometry of I3- is :
(1) Triangular  (2) Linear (3) Tetrahedral (4) T-shape
 
38. The half life of a radio active element is 140 days. 1 gm. of this element after
560 days will become :
(1)   1
 gm       (2)    1 gm  (3)     1gm.   (4)    1 gm.
       16                       4                       8                                2
 
39. The volume concentration of hydrogen peroxide 6.8% concentration will be :
(1) 5  (2) 11.2 (3) 22.4 (4) 20
 
40. Which of the following on combustion give maximum energy :
(1) Ethane (2) Propane (3) Methane (4) Butane
 
                                                         Anhy. AICI    
3
41. C6H6 + CH3CI                 C6H5CH3 + HCI  The name of above reaction is :
(1) Gattermann (2) Reimer-tiemann 
(3) Friedel-Craft (4) Cannizaro
 
42. The oxidation state of Cr in K Cr O  is :
2 2 7
(1) + 4  (2) + 3  (3) + 6  (4) + 5
 
43. The natural rubber is the polymer of :
(1) 1, 3- butadiene (2) polyamide  (3) isoprene (4) none of these
 
44. Nylone-66 is a :
(1) polyester (2) polyamide  (3) polyacrylate (4) none of these
 
 

ANSWER SHEET
1.(2) 2.(3) 3.(3) 4.(2) 5.(2) 6.(4) 7.(1) 8.(3) 9.(1) 10.(4) 11.(1)
12.(1) 13.(2) 14.(4) 15.(2) 16.(4)17.(3)18.(2)19.(2)20.(2) 21.(1) 22.(2)
23.(3) 24.(4) 25.(4) 26.(3) 27.(3)28.(3)29.(2)30.(3)31.(3) 32.(1) 33.(2)
34.(3) 35.(2) 36.(3) 37.(2) 38.(1)39.(4)40.(4)41.(3)42(3) 43.(3) 44.(2)
 
Friend hope youu will find them useful please do comment i will post some more such questions  cheers
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1. The hybridization state of C atom in butendioic acid is :
2 3
(1) sp   (2) sp   (3) both two  (4) sp
 
2.  Which of the following is not a isomer of pentane :
(1) n-pentane
(2) 2, 2-dimethy 1 propane
(3) 2, 3-dimethy 1 butane 
(4) 2-methy 1 butane
 
3. The oxidation number of C atom in Ch CI  and CCI  are respectiv
2 2 4
(1) -2 and ? 4  (2) 0 and ? 4 (3) 0 and 4 (4) 2 and 4
 
4. Which of the following dissolves in lonic solvents :
(1) C H  (2) CH OH (3) CCI  (4) C H 
6 5 3 4 5 12
 
5. The conjugate acid of HS is :
-2
(1) S  (2) H S  (3) both two  (4) none
2 2
 
6. Phenolphthalein of pH range [8-10] is used in which of the followin
titration as a suitable indicator :
OH and HCI
(1) NH
4
(2) NH
OH and HCOOH
4
(3) NH OH and C H O 
4 2 4 2
(4) NaOH and C
O H 
2 4 2
 
7. Which of the following is iron are :
(1) Malachite  (2) Hernatite (3) Siderite  (4) Limonite
 
8. The molar concentration of chloride ions in the resulting solution o
 will be :
ml.of 3.0 M NaCI and 200 ml. of 4.0 M BaCl
2
(1) 1.7 M (2) 1.8 M (3) 5.0 M (4) 3.5 M
 
9. Which of the following has least bond energy :
-2 - +
 (2) N   (3) N   (4) N 
(1) N
2 2 2 2
 
10. Which of the following species has highest bond energy :
-2 + -
(1) O  (2) O   (3) O  (4) O 
2 2 2 2
 
11. Which of the following compound is not aromatic :
(1) 1, 3-cyclobutene 
(2) pyridine
(3) furane
(4) thiophene
12. Which of the following compound is used as refrigerant :
(1) CCI F 
2 2
(2) CCI
 
4
(3) CF 
4
(4) Acetone
 
13. Which of the following is weak acid :
(1) C H  (2) CH -C=CH (3) CH =CH    (4) CH -C=C-CH 
6 6 3 2 2 3 3
 
14. L.P.G. mainly consist of the following :
(1) Methane (2) Hydrogen  (3) Acetylene  (4) Butane
 
-9
15. The solubility product of CaCo  is 5 x 10 . The solubility will be :
3
-5 -5 -4 -9
(1) 2.5 x 10   (2) 7 x 10  (3) 2.5 x 10   (4) 2.2 x 10 
 
16. The outer electronic configuration of alkali earth metals is :
10 1 6
(1) nd
 (2) ns   (3) np   (4) ns 
2
 
17. The nature of 2, 4, 6-trinitrophenol is :
(1) Neutral (2) Basic (3) Acidic (4) Weak basic
 
18. Which of the following group is sharp ortho and para directive :
(1) ?C H  (2)-OH  (3) ?CH  (4) ?CI
6 5 3
 
19. By which of the following process hydrocarbons are found from petroleum :
(1) combustion
(2) fractional distillation
(3) addition
(4) all above
 
20. A sample of petroleum contains 30% n-heptane, 10% 2-methyl hexane and
60% 2, 2, 4-trimethyl pentane, the octane no. of this sample will be :
(1) 30% (2) 60% (3) 10% (4) 70%
 21. In which of the following halogens p-electrons does not take part in
resonance :
(1) CH
=CH-CH Cl  (2) BrC H 
2 2 6 5
H Cl   (4) CH =CHCl
(3) C
6 5 2
22. Which of the following statement is false :
(1) 40% solution HCHO is known as formalin
(2) HCHO is least reactive in its homologous series
(3) The B.P. of isovarelaldehyde is less than n-varelaldehyde
(4) The boiling point of ketones are higher than that of aldehydes
23. If n + ?? = 8 then the expected no. of orbitals will be :
??
(1) 4  (2) 9  (3) 16  (4) 25
Alc. KOH        2Cl             Ca(OH)
             
2 2
24. A              B             C                   here the compound C will be :
(1) Lewsite (2) Westron (3) Acetylene tetra chloride (4) Both 2 and 3
 
25. Which of the following is least hydrolysed :
(1) BeCl  (2) MgCl  (3) CaCl  (3) BaCl 
2 2 2 2
 
26. The laughing gas is :
O  (2) NO  (3) N O (4) N O 
(1) N
2 4 2 2 5
 
-6
27. The hydrogen ion concentration of a solution is 3.98 x 10  mole per liter. The
pH value of this solution will be :
(1) 6.0  (2) 5.8  (3) 5.4  (4) 5.9
 
28. The reaction of sodium acetate and sodalime gives :
(1) Butane (2) Ethane (3) Methane (4) Propane
 
29. Which of the following acids does not contain ? COOH group :
(1) Carbamic acid (2) Barbituric acid 
(3) Lactic acid  (4) succinnic acid
 
30. Which of the following compound of xenone does not exists :
(1) XeF  (2) XeF  (4) XeF  (4) XeF 
6 4 5 2
 
31. FeSO
, 7H O is :
4 2
(1) Mohr?s salt     (2) Blue vitriol (3) Green vitriol  (4) White vitriol 
 32. The solution of BiCl3 in dil. HCI when diluted with water white preci
formed which is :
(1) Bismith oxychloride (2) Bismith oxide
(3) Bismith hydroxide  (3) none of these
33. The strongest acid is :
(1) acetic acid
(2) trichloroacetic acid
(3) dichloracetic acid
(4) monochloroacetic acid
34. The false statement regarding alkane is :
(1) This does not perform polymerization reaction
(2) This does not gives elimination reaction
(3) It does not disappear the colour of dilute KMnO
 solution

(4) It does not decolourise bromine water
35. Which of the following is strongest base :
(1) C H NH   (2) CH NH 
 
36. Which of the following aromatic compound gives sulphonation reaction very
easily :
(1)  Chlorobenzene  (2) Nitrobenzene (3) Toluene (4) benzene
 
 
37. The geometry of I3- is :
(1) Triangular  (2) Linear (3) Tetrahedral (4) T-shape
 
38. The half life of a radio active element is 140 days. 1 gm. of this element after
560 days will become :
(1)   1
 gm       (2)    1 gm  (3)     1gm.   (4)    1 gm.
       16                       4                       8                                2
 
39. The volume concentration of hydrogen peroxide 6.8% concentration will be :
(1) 5  (2) 11.2 (3) 22.4 (4) 20
 
40. Which of the following on combustion give maximum energy :
(1) Ethane (2) Propane (3) Methane (4) Butane
 
                                                         Anhy. AICI    
3
41. C6H6 + CH3CI                 C6H5CH3 + HCI  The name of above reaction is :
(1) Gattermann (2) Reimer-tiemann 
(3) Friedel-Craft (4) Cannizaro
 
42. The oxidation state of Cr in K Cr O  is :
2 2 7
(1) + 4  (2) + 3  (3) + 6  (4) + 5
 
43. The natural rubber is the polymer of :
(1) 1, 3- butadiene (2) polyamide  (3) isoprene (4) none of these
 
44. Nylone-66 is a :
(1) polyester (2) polyamide  (3) polyacrylate (4) none of these
 
 
 
ANSWER SHEET
1.(2) 2.(3) 3.(3) 4.(2) 5.(2) 6.(4) 7.(1) 8.(3) 9.(1) 10.(4) 11.(1)
12.(1) 13.(2) 14.(4) 15.(2) 16.(4)17.(3)18.(2)19.(2)20.(2) 21.(1) 22.(2)
23.(3) 24.(4) 25.(4) 26.(3) 27.(3)28.(3)29.(2)30.(3)31.(3) 32.(1) 33.(2)
34.(3) 35.(2) 36.(3) 37.(2) 38.(1)39.(4)40.(4)41.(3)42(3) 43.(3) 44.(2)
 
Friend hope youu will find them useful please do comment i will post some more such questions  cheers
Catalogs Discussion Forums -> Mechanics -> Sign convention get rated -> Go to message
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can anyone tell me the sign convention used
Case 1  when a body is dropped from tower height H wit velocity v , gravity g
 
Case 2 when body is thrown upward from tower height H wit velocity v , gravity g
 
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A uniform pole 50 kg is placed vertically on a rough surface of  =0.3.Lenght of pole is 8 m.A 500 N horizontal force is given to the pole suddenly at a height of 2m above the ground.Determine the acceleration of the topmost point of the pole..(g=9.8)....
 
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A stick length L and mass M lies on a frictionless horizontal surface on which it is free to move in any way a ball of mass m moving with speed v collides elastically with the stick as shown in the figure . it after collison the ball comes to rest then mass of ball should be
 
Ans M/4
 
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Catalogs Discussion Forums -> Mechanics -> Easy qns but not getting ans -> Go to message
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A rigid body each of length L fastened together to form letter H
The body is free to rotate about a horizontal axis that runs along the length of one of the legs of H The body is allowed to fall from rest from a position in which plane of H is horizontal
 
What is angular speed of the body when plane of body is vertical
 
Ans 1.5(g/l)
 
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Catalogs Catalogs -> Physics -> Problems in general phyics -> Go to message
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Very good book i am also using it & altough bit tough good for exams like AIIMS & IIT whic is everyones dream so it is a dream book
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STUDY TIPS
  Combination of Subjects
Study a combination of subjects during a day i. e. after studying 2Ò3 hrs of mathematics shift to
any theoretical subject for 2 horrs. When we study a subject like math, a particular part of the
brain is working more than rest of the brain. When we shift to a theoretical subject, practically the
other part of the brain would become active and the part studying maths will go for rest.
 
  Revision
Always refresh your memory by revising the matter learned. At the end of the day you must revise
whatever youÌve learnt during that day (or revise the previous days work before starting studies
the next day). On an average brain is able to retain the newly learned information 80% only for 12
hours, after that the forgetting cycle begins. After this revision, now the brain is able to hold the
matter for 7 days. So next revision should be after 7 days (sundays could be kept for just
revision). This ways you will get rid of the problem of forgetting what you study and save a lot of
time in restudying that topic. 
 
  Use All Your Senses 
Whatever you read, try to convert that into picture and visualize it. Our eye memory is many times
stronger than our ear memory since the nerves connecting brain to eye are many times stronger
than nerves connecting brain to ear. So instead of trying to mug up by repeating it loudly try to
see it while reapeating (loudly or in your mind). This is applicable in theoritical subjects. Try to use
all your senses while learning a subject matter. On an average we remember 25% of what we
read, 35% of what we hear, 50% of what we say, 75% of what we see, 95% of what we read,
hear, say and see.
 
  Breathing and Relaxation
Take special care of your breathing. Deep breaths are very important for relaxing your mind and
hence in your concentration. Pranayam can do wonders to your concentration, relaxation and
sharpening your mined (by supplying oxygen to it). Aerobic exercises like skipping, jogging,
swimming and cycling are also very helpful.
 
The most powerful weapon on earth is
human soul on fire!
 
Hope you will find them useful please comment
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Question 1
Let f and g be defined by f(x) = |x|, xÎ R, and g(x) = x, xÎ R. Find f + g, f - g, fg and f/g.
Ans.
( f + g )( x )
= 2x x ³ 0
  0 x < 0
       
( f - g )( x ) = 0 x ³ 0
  -2x x < 0
       
(fg)(x) = x2 x ³ 0
  -x2 x < 0
       
(f/g)(x) = 1 x > 0
  -1 x < 0
f/g is not defined at x = 0.
Question 2
Find the inverse of the function
F(x) = x + 1, x ¹ 1
             x - 1
Ans.
Let us see whether the given function is invertable
Let               x1 , x2 ¹ 1                      x1 ¹ x2
Then             x1 + 1                    ¹           x2 + 1
And               x1 - 1                  ¹           x2 - 1
\                 x1 + 1              ¹            x2 + 1
                   x1 - 1                ¹            x2 - 1
Þ                f(x1)                  ¹              f(x2)
\                 f is invertable function
Now y = x + 1 or xy - y = x + 1/X - 1

Or x(y - 1) = y + 1 or X = y +1/y - 1

we are given f = {(x,y) : y = x + 1/x - 1}

\            f-1 = {(y,x) : y ¹ 1 , x = y +1/y - 1 }
Question 3
Find fof-1 and f -1of   the function
F(x) = 1/x , x ¹ 0.
Also prove that fof-1 = f-1of
Ans.
            f(x) = 1/x
\          f-1 = { ( 1/x = y,x)}
                 = { (y, 1/y) }
\          f-1 (x) = 1/x
\          fof -1 (x) = f(1/x)     =   1     = x
                                                       1/x
Also       f -1of (x) = f-1 (1/x)   =   1   =  x.
                                                           1/x
\          fof -1 (x)  = f -1 of (x)
Hence f -1 of = f -1 of
Question 4
Evaluate lim     2x2 + 3x
                x®¥          x2 +1
Ans.
Put x = 1/y, so that when x®¥, y®0.
\   lim      2x2 + 3x        = lim       2/y2 + 3/y
    x®¥       x2 +1             y®0        1/y2 +1
                                   = lim       2 + 3y      = 2 + 0    = 2.
                                     y®0      1 +y2          1 + 0
Question 5
The profit function of a manufacturing firm is given by P(x) = -x3/3 + 729x - 2500. Find x so that the firm attains maximum profit, where x is the number of items manufactured.
Ans.
The profit function is
     P(x) = -x3/3 + 729x - 2500
     P1(x) = -x2 + 729; where p 1 is the d(p(x))/dx
\  P1 (x) = 0 give us -x2 + 729 = 0
or x = 27.
[ -27 is rejected as x is number of items]
Now P11 (x) = -2x
Which is -ve at x = 27
\    P(x) attain the maximum value at x = 27
\    Number of items (x) manufactured by firm = 27.
Question 6

          _______________________  
If y = Öcosx + Ö cosx +Ö cosx+ ?..¥ then prove that (2y -1) dy/dx + sinx = 0.
Ans.
we are given that
           _______________________
    y = Öcosx + Ö cosx +Ö cosx+ ?..¥
           _______
       = Öcosx + y
    or y2 = cosx + y
Differentiating both sides w.r.t. x1 we get
     2y dy            = -sinx + dy
         dx                               dx
or 2y dy - dy sinx = 0
        dx   dx
\  (2y - 1) dy/dx + sinx = 0.
Question 7
Show that x/sinx is an increasing function in the intercal 0< x < p/2.
Ans.
Let           f(x) = x/sinx
Then         f1(x) = sinx - xcosx
                              sin2x
Now   sin2x   >0 for     0< x < p/2
                   [ In fact sin2 x> 0 < " x]
we know that
                   tanx > x for 0 < x < p/2
\           sinx > x  for 0 < x < p/2
             cos
\      sinx - x cosx > 0 for 0 < x < p/2
\      f1(x) = sinx - x cosx   > 0 for 0 < x < p/2
                      sin2x
\     f (x) is increasing in the interval { 0, p/2}
Question 8
Find the deviative of cot( 2x +1) w.r.t. x using the first principles.
Ans.
     Let y = cot [ 2 x +1]
\        y +dy = cot {2(x + dx) + 1 }
          or dy = cot {2 (x +dx) +1} - cot (2x +1)
          = cos (2x+1+ 2dx )    -     cos(2x+1)
             sin (2x+1+2dx)             sin (2x+1)

          =  cos (2x+1+2ds) sin (2x+1) - sin(2x+1+2dx) cos (2x+1)
                            sin (2x+1+2fx)   sin ( 2x+1 )
         =  sin (2x +1 - 2x -1 -2dx)
           sin(2x +1 +2dx) sin(2x+1)
\                    dy         =                 -sin (2dx)             
         sx                 sin(2x+1 + 2fx) sin(2x +1)dx
\ lim                                     dy   =     lim   -sin(2dx)     =                   lim-1         
dx ®0                                     dx        dx ®0    sin(2x+1+2dx)       sin(2x+1)dx
\    dy           =           -1                 x 1        x    2
       dx              sin(2x+1) sin(2x +1)
                   =          -2      
                         sin2 (2x +1)
= -2 cosec2 (2x +1)
Question 9
                                                                                                      ____
Use Lagrauge's mean value theorm to determine a point P on the curve y = Ö x - 2 defined in the interval [2,3] where the tangent is parallel to the chord joining the end points on the curve.
Unit - 2 (Integral Calculus)
Ans.           _____
Here f(x) = Ö x - 2
        _____
Now Ö x - 2 is defined for all values of x ³ 2
\     f(x) is defined in the interval [2,3]
again       f1(x)       =       1     
                                 2Ö x - 2
     1         is defined for all values of x > 2.
2Ö x - 2
\ f(x) is derivable in the interval ]2,3[.
Thus both the conditions of LMV therom are satisfied.
\ by LMV theorem there must exists at least one C in the interval ]2,3[ at which the tangent is parallel to the chord joining the end points on the curve, such that.
F1 ( C )         =      f(3) - f(2)
                               3 - 2
or      1              =                   Ö3 -2    -     Ö2 - 2
     2Ö c - 2                          1
\            1            =            1
          2Ö c - 2
or       2Ö c - 2        =             1
\       4(c - 2)        =              1
or         c - 2         =             ¼
\          c = ¼ + 2 = 9/4 E ]2,3[
\ Now f (9/4) = Ö9/4 - 2 = Ö¼ = ½
Hence the tangent is parallel to the chord at the point (9/4, ½).
Question 10
Evaluate : ò14 |x - 2| dx
Ans.
          ½x - 2½ = x - 2 if x ³ 2.
And ½x - 2½ = -x - 2 if x < 2.
\      ò14½x - 2½dx     = ò12 - (x - 2) dx + ò24 (x - 2) dx

= ( -x2/2 + 2x)12 + (x2/2 + 2x)24
= [ (-4/2 + 4 ) - ( -1/2 + 2)] + [(16/2 -8) (4/2 -4)
= 2-3/2 + 0 +2           =       5/2.

Question 11
Evaluate
òxex/(x +1)2 dx
Ans.
              I = ò x e x           dx
                   (x + 1)2
                = òex [ 1/ (x +1)- 1/(x + 1)2 ] dx
               = òex [f(x) + f1(x) ], where f(x) = 1/ (x+1)

               = ex f(x) + c

               = ex /(x+1) + C.

Question 12
Evaluate
            ______
ò Öx / Öa3 - x3 dx
Ans.
          Let x 3/2 = t. then 3/2 Öx dx = dt
\                             Öx dx = 2/3 dt
\                  I = òÖ x a3 - x3 dx     =        ò Ö2/3 dt/Öa3 - t2
                                                   = 2/3 ò dt/ Ö( a 3/2) 2 - t2

                   = 2/3 - sin-1 t/a3/2 + c {\         ò dx/Öa2-x2 = sin-1 x/a = c}

= 2/3 sin -1 (x/a)3/2 + c.

Question 13
Evaluate ò-11 ex dx as the limit of a sum.
Ans.
Let f (x)         =         ex . Let nh = 1- ( -1) =   2.

        ò -11 exdx =   lim h [ f (-1)+f(-1+h) +f(-1+2h)+ ------+f(-1+n-1h) ]
                   h ® o
              =  lim h[ e-1+e-1+h+e-1+2 h+-------+e-1+(n-1)h ]
                 h ® o
              =  lim h [e-1{ 1+eh+e2h+---------+e +(n+)h } ]
                 h ®o
             = lim h     [e-1{ 1-enh/1-eh } ]
                h ® o
             = lim        h/1-eh .    lim e-1 ( 1-enh)
                h ® o                    h ®o
             = (-1)              [ e-1(1-e2)]
               lim eh-1/h
               h ® o
            = e-1(e2 -1)}e2
                    1
             = e-1
                  e

Question 14
Find the aver of the region bounded by the two parabolas y = x2 and x = y2
Ans.
Sloving the equation y = x2 and x = y2 , the points of the intersection of the two curves are 0(0,) and P(1,1). The requried area is PROS in fig. (1.1) Y

\ A = ò y dx y = x2
\ Requried area A
= area OSPQ - area ORPQ
= ò01 Öx dx - ò01 x2 dx
=[2/3 x 3/2]01 - [x3/3]01
= 2/3 - 1/3 = 1/3 sq units.

Question 15
Prove that ò0p/4 log(1 + tanq) dq = p/8 log 2.
Ans.
    Let                   I = ò 0 p/4 log(1 + tanq) dQ  
                             = ò0 p/4 log [ 1 + tan(p/4 -Q) dQ
                                 [\       ò0a f(x) dx = ò0a f ( a - x) dx]
                            = ò0 p/4 log [1 - tanQ/1 + tanQ] dQ
                            = ò0 p/4 log [ 2/1 + tanQ ] dQ
                            = ò0 p/4 logdQ  - ò0 0 p/4 log [1 - tanQ] dQ

             \         I          = log 2 [0] 0 p/4 - I
or            2 I         = log 2 [ 0 p/4]
or              I         =          p/8 log 2.

Question 16
Evaluate:
òx2 + 1/x4 + 1 dx
Ans.
                                                                    ò     x2 + 1/x4 + 1 =dx
                   = ò(1+1/x2)/(x2 + 1/x2) dx
                   = ò    1 + 1/x2                dx
                       x2 + 1/ x2 - 2 +2
Let               x - 1/x       =      z, so that ( 1+1/x2) dx = dz
                                                 òx2 + 1/x4 + 1   dx   =     ò  dz/ z2 + 2 =  ò         dz            / z2+(Ö2)2
                  = (1/Ö2)( tan-1    z/Ö2 )+ c [\ ò 1/x2 + a2 dx = 1/a tan -1 x/a]
                  = 1/Ö2 tan-1      x - 1/x/Ö2 + c
                  = 1/Ö2 tan-1      x2 - 1/Ö2x + c

Question 17
Evaluate :
òx4/x4 - 1 dx
Ans.
Let                   x4                             º                  x4         
                     x4 - 1                              (x-1)(x+1)(x2+1)
                    = 1 +    A    +    B        +       (x + D) ?..(1)
                              x-1       x+1               x+1
Multiplying by x4 - 1   we get
                                          º
  (x4 - 1) + A (x+1) (x2+1) +B (x - 1) (x2 +1)
                   + (x + D) (x + 1) ( x - 1 ) ?. (2)
Putting x = 1, -1 in (II) , we get
1= A (2) (2) And 1 = B(-2)(2)
or A = ¼ and B = -1/4
Equating ¥ efficients of x3 in (2) , we get
A + B +C = 0
But a = ¼ and b = -1/4
\ c = 0
Puuting x = 0 in (2) , we get
0 = -1 + A -B - D
or D = -1 +A -B
= -1 + ¼ + ¼ = -1/2
\from (1)
         x4             =              1           +           1          -       1     -       1 .
       x4 -1                                                 4(x-1)          4(x+1)       2(x2+1)
       x4/x4 -1     dx          =              1           +           1/4(x-1)         -    1/4/x+1      -     1/2(x2+1).dx 
= x + ¼ log (x -1 ) -1/4 log (x + 1) -1/2 tan-1 x + c
= x + ¼ log x - 1 -1/2 tan -1 x + c
                 x+1

Question 18
Find the area of the region bounded by the curve c:y = tanx, tangent drawn to C at x =p/4 and the x - axis.
Ans.
Requried area = shaded area on the figure
= Area (OPR) - area (DPQR)
                 = ò p/4 tanx dx - DPQR ??..(1)
To find DPQR, we proceed as follows :
Now Point P is ( p/4 , 1) Y

\ y = tan x
\ dx/dy = sec2x
\Slope of tangent at P = sec2p/4 = 2
i.e., tanQ = 2
\ QR = PR cot Q
= 1 x ½ = ½
\ Area of DPQR = ½ x ½ x 1 = ¼ sq.unit. q R
\ from (1)
Required area = (log sec x )p/4 - ¼
= log 02 - ¼
=[1/2 log2 - ¼ ] sr.units.

Question 19
Evaluate : òop/4  (sinx + cosx)/(9+16 sin2x)  dx
Ans.
Let I = òo p/4 sinx + cosx dx
                   9+16 sin2x
        = òo p/4               cosx + sinx                 dx
                       9+16 { 1-(sinx - cosx)2}
Let     sinx - cosx = t ,                then ( cosx +sinx) dx = dt
When        x = 0, t = -1 and when    x = p/4, t = 0
\            I   =    ò-1o          dt        
                              9 + 16 ( 1 - t2)
                  = ò-1o             dt     
                                   25 - 16t2
                  = ò-1o              dt     
                                    52 - (4t)(4E)2
                  = 1/2x5 x ¼ log [ 5 + 4t/5 - 4t]o-1

                  = 1/40 [log1 - log(1/9)]
                  = 1/40 (log9) = 1/40 log 32
                  = 1/20 log3.

Question 20
                                   _______
Evaluate ò(3x - 2) Öx2 +x+ 1  dx.
Ans.
      
Let I = ò(3x - 2) Öx2 +x+ 1 dx.
Here d/dx (x2 +x+ 1) = 2x +1

\ we express 3x - 2 in terms of 2x +1
Now 3x - 2 = 3/2 (2x+1) -7/2

\ I = ò{ 3/2 (2x + 1) - 7/2 } Öx2 +x+ 1 dx.

= 3/2 ò (2x +1) Öx2 +x+ 1 dx - 7/2 òÖx2 +x+ 1 dx.
= 3/2 I1 - 7/2 I2 + c

Now I1 = ò(2x + 2) Öx2 +x+ 1 dx.
Let x2 +x+ 1 = t , then (2x +1) dx = dt.
\ I1 = ò Öt dt = 2/3 t 3/2 = 2/3 (x2 +x+ 1)3/2

and I2 = ò Ö x2 +x+ 1 dx = ò Ö ( x + ½)2 + (Ö3/2)2 dx.

= (x + ½) Öx2 +x+ 1 + ¾ log [(x + ½) Ö x2 +x+ 1] +c
                  2                      2                   Ö3/2
= (2x + 1) Ö x2 +x+ 1 + 3 log [(2x + 1) Ö x2 +x+ 1] +c
4 8 Ö3

\ from (1)                                    
 I = 3/2 . 2/3 (x2 +x+ 1)3/2 - 7/2[(2x+1) Ö x2 +x+ 1 +
                                                                                4
3/8 log [{2x +1 +2 Öx2 +x+ 1}] +c
                                     
= (x2 +x+ 1)3/2 - 7/8 (2x +1) Öx2 +x+ 1
- 21/16 log [ 2x + 1 + 2 Ö x2 +x+ 1] +c
                                     Ö3

Question 21

Prove that òop/2 Öcotx/Cotx + Ötanx)    dx = p/4
Ans.
Let I = òop/2                       Öcotx / (ÖCotx + Ötanx)           dx
 
= òop/2 Öcotx (p/2 -x)       _____         dx
                                ÖCotx (p/2 -x) + Ötanx (p/2 -x)
[oa  f(x) dx = òoa f(a - x)dx]
= òop/2 Ötanx dx /    Ötanx + Öcotx
    \ I + I = òop/2 Öcotx/      Ötanx + Öcotx          dx      +       òop/2 Ötanx/Öcotx + Ötanx         dx
= òop/2 Öcotx + Ötanx/Öcotx + Ötanx   dx
      = òop/2 1.dx
= [x]op/2
= p/2

\2I = p/2
or I = p/4.

Question 22
                                                           _____
Solve the differential equation a + x ) dy/dx + x = 0.
Ans.
                                            ____
The given equation is( Öa + x) dy/dx + x = 0
Þ dy = -x /Öa + x    dx
Þ òdy = - ò    x dx /    Öa + x
                                                                 
Þ òdy = - ò a + x - a /           Öa + x dx
                                                                
                  ____
Þ y = - ò Öa + x dx + òa (a+ x) -1/2 dx
Þ y = - (a + x)3/2 + a . (a + x) ½ + C
                 3/2                     1/2
Þ y = -2/3 (a +x) 3/2 + 2a Öa + x + C.
which is the required solution.

Question 23
Find the differential equaion which corresponds to the equaion Y = ke sin-1x
Ans.
We are given Y = k . e sin-1x???.(1)
Defferentiating w.r.t. x we get
dy/dx = k.esin-1x 1/Ö1- x2 ???(2)
Putting k = y      from (1) in (2) , we get
                 Sin-1 x
dy/dx =     y      .   esin-1x
               esin-1x    Ö1-x2
or dy/dx =    y/Ö1-x2    
  Which is the required differential equation.