ya i got ur method

thanks

 

is the ans  c - c_V = R(1-y/t)

 

in this soln. XCY means ^xC_y for example 4C1 means ⁴C₁

 

total cases are

(5C4 * 3C1 * 2C1) + (5C3 * 3C2 * 2C1) + (5C3 * 3C1 * 2C2) + (5C2 * 3C3 * 2C1)

+ (5C2 * 3C2 * 2C2) + (5C1 * 3C3 * 2C2)

 

 

=  30 + 60 + 30 + 20 + 30 + 5

=  175

SO THE ANSWER SHOULD BE 175

 

 

 

 

 

hi joyfrancis

it's not given that volume in sample a is same as that in sample b

 

 

see  lets take two boys b1 & b2.

first case

6 apples are to be distributed

if b1 gets 1 apple then b2 will get 5 therefore we write (1,5)

similarly no. of cases are

(0,6);(1,5);(2,4);(3,3);(4,2);(5,1);(6,0)

therefore the total ways are 7 but we have a condition that both boys should get atleast one fruit therefore (0,6) & (6,0) are not valid

therefore total ways of distributing apples = 5

similarly total ways of distributing bananas & oranges is 7 & 10

 therefore total ways = 7*5*10 = 350

  

how can pressure be directly proportional to volume.

if pressure increases volume has to decrease & vice versa.

 

 

yes joyfrancis  u're correct it's not given that the process is adiabatic.

by the way i read this question in i.e irodov's book.

i accept ur answer kab

thanks a lot aditya for the solns.

 

Q1.lim    cos(2x)-1/cosx-1]

      x-->0 

Q2.lim            [tan(2x)/x-(pie/2)]

     x--->(pie/2)    

 

oh i got it as 120

hi

the soln is as following

1.the no. of solns of the word suriti are 6!/2! = 360

2.now let's count the words which wil come before suriti which are words starting with i,r,si,sr,st,sui

3.words starting with i=5!;r=5!/2!;total=60+120=180

4.words starting with si=4!;sr=4!/2!;st=4!/2!;total=24+12+12=48

5.words starting with sui are 3!=6

6.adding all the bold values we get 234

7.now two words are left suriit & suriti but suriit will be placed before suriti there fore suriit will get ranked 235 & suriti 236.

THEREFORE A) IS THE CORRECT ANSWER