Messages posted by priyesh

hi joyfrancis the soln. is as follows

(1+cosx)(2sinx-cosx)=sin²x

2sinx-cosx+2sinxcosx-cos²x-sin²x=0

2sinx-cosx+2sinxcosx-1=0

1(2sinx-1)+cosx(2sinx-1)=0

(1+cosx)(2sinx-1)=0

cosx=-1

or

sinx=1/2

therefore

x=2npi +- pi

x=npi + (-1)ⁿpi/6

i got his question let me explain it

suppose u have to enter a password of 4 digits in a computer which are distinct and non-repetitive(note that zero is excluded).but if u enter the password with a no. more than four digits then the if the sequence is present in that set of nos. the password will get excepted.for eg: the password is 3692 now if i enter

145682436926827 . the password is excepted.now in the question asked by joy francis you have to tell a no. which if entered contains all the 4 digit passwords in it i.e the computer will always say password accepted no matter what 4 digit password it is.

Now diid you get the question?

hi bhushan

the ans to this ques is -2E[1/4(

-2x) , 2]

where E(x,m) is an elliptical integral of second kind.

ya i got ur method

thanks

is the ans c - c_V= R(1-y/t)

in this soln. XCY means ^xC_yfor example 4C1 means ⁴C₁

total cases are

(5C4 * 3C1 * 2C1) + (5C3 * 3C2 * 2C1) + (5C3 * 3C1 * 2C2) + (5C2 * 3C3 * 2C1)

+ (5C2 * 3C2 * 2C2) + (5C1 * 3C3 * 2C2)

= 30 + 60 + 30 + 20 + 30 + 5

= 175

SO THE ANSWER SHOULD BE 175

hi joyfrancis

it's not given that volume in sample a is same as that in sample b

see lets take two boys b1 & b2.

first case

6 apples are to be distributed

if b1 gets 1 apple then b2 will get 5 therefore we write (1,5)

similarly no. of cases are

(0,6);(1,5);(2,4);(3,3);(4,2);(5,1);(6,0)

therefore the total ways are 7 but we have a condition that both boys should get atleast one fruit therefore (0,6) & (6,0) are not valid

therefore total ways of distributing apples = 5

similarly total ways of distributing bananas & oranges is 7 & 10

therefore total ways = 7*5*10 = 350

how can pressure be directly proportional to volume.

if pressure increases volume has to decrease & vice versa.

yes joyfrancis u're correct it's not given that the process is adiabatic.

by the way i read this question in i.e irodov's book.

i accept ur answer kab

ans given is 1.33 so i think kab u're correct

Q. calculate the value of gamma (i.e Cp/Cv) for a gaseous mixture consisting 2.0 moles of oxygen & 3.0 moles of carbon dioxide.The gases are assumed to be ideal.

thanks a lot aditya for the solns.

Q1.lim cos(2x)-1/cosx-1]

x-->0

Q2.lim [tan(2x)/x-(pie/2)]

x--->(pie/2)

refer to soln of abc=24 on post http://www.goiit.com/posts/list/15/4015.htm

oh i got it as 120

hi

the soln is as following

1.the no. of solns of the word suriti are 6!/2! = 360

2.now let's count the words which wil come before suriti which are words starting with i,r,si,sr,st,sui

3.words starting with i=5!;r=5!/2!;total=60+120=180

4.words starting with si=4!;sr=4!/2!;st=4!/2!;total=24+12+12=48

5.words starting with sui are 3!=6

6.adding all the bold values we get 234

7.now two words are left suriit & suriti but suriit will be placed before suriti there fore suriit will get ranked 235 & suriti 236.

THEREFORE A) IS THE CORRECT ANSWER

the q1 is an hypothetical case because the spring will never get compressed & the motion of the mass will be of shm.

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