Messages posted by Arun Kulsherstha

apply formula grams law of diffusion solve first part

good book is elixir u must read chapter 3 and stereochemistry always
remember stereo is very imp for jee available at book stall frm g.k
pub and than any prb ask

in periodic table down the gr basic nature of oxide increases while across the pd acidic nature decides by fajans rule, ionic potential=charge on cation/radius of cation.

i think boron of more volume due to more no of shells than hydrogen[284]

actully in enol form there is attachement of h atom with doubly bonded oxygen so simultaneous shift of hydrogen atom and pi bond by resonance and get stabilisationbut in some cases like 2,4 diketonederivatives and aromatic like phenole enol is more stable due to h bonding or aromatic stability.

Can you elaborate your question more as critical temperature is usually associated with gases and not liquids

salicylic acid when reacts with zinc forms benzoic acid, because it removes OH group from the ring.

Yes, Inorganic chemistry by O.P. Tandon is a good book.

Also Problem solution book in Inorganic by "P Bahadur" is a good one.

Other referances are: books by J. D. Lee and Sharp

entropyfor isolated system increas in an irreversable process while remains unchanged in a rever process ref 2nd law of termo

acording to kekule benzene forms equal resonanting structure so all have equal stability.there r many theory refer

it is a high spin complex because water is a weak ligand so it form outer orbital complex sp3d2 hybridistion

this topic contains many concept but major r salt hydrolysis,buffer,solubility product and ph probs but u improove ur th and numericals both,if u really want top materials send some one to my academy in jaipur i will give u original th and ques expected in jee 007

there r many rec like eletrophilic addtion ,nupilic addtion,nu subustitution ,free radical substi ,elimination etc .hyperconjugation means no bond resonance,explain stability of alkene consult my book elixir for this

Step 1. for acid base titration between acidic H⁺ & NaOH we apply conservation of meq so factor is y and meq. of NaOH is 1.8 so, (W*y/mol.wt)*1000=1.8..................(1)

Step 2. Apply redox titration b/w oxilate ion and (MnO₄)^- and again conservation of meqs. where factor of oxilate is 2z so w*2z*1000/Mol.wt=24*0.1*5 ...........(2)

Step 3. Apply in any rection charge on cation =charge on anion.So we create simplest ratio b/w x,y,z

Step 4. by this we calculate mol.wt of salt

Step 5. After calculating mol.wt we easily find out 4th unknown i.e. n.

In solution Cu⁺²is more stable than Cu⁺¹due to high solvation energy in case of Cu⁺²ion.Actually Cu⁺² undergo disprportionation to form Cu⁺² and Cu⁰ ion.

Firstly, the answer u got is the correct one.It may be possible that it is given wrong in the book you refferred.

To find empirical formula follow the given steps:

1. for element A- 75/75.8 = .989

2. for element B: 16/24.2 = 0.66

3. get the simplest ratio as

for A - .989/.66 = 1.5 approx.

for B - .66/.66 = 1(divide both of them by the smaller one of the two)

4. so we get the formula

A₃B₂

They are weak intermolecular forces of attraction.Dipole-dipole,dipole-induced dipole,London dispersion forces are included in VanderWaal's Forces.

They are universal forces.

As about your query abt. Polarisable mlolecules,they are non polar (covalent)

but +ve and -ve ends or poles are created.

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