goIIT: IIT JEE AIEEE CET WBJEE VITJEE BITSAT IIIT AICET Engineering Entrance Experts, Student Discussion Community, IIT JEE Preparation Online

since the coefficient of friction or frictional force is changing the cooter will pass through the path that offers the least resistance .

50)
the natural length is 0.4 and let the xtended length be 0.4+x
mg=kxcos@
cos@=mg/kx
which is also equa to 0.4/0.4+x
solving which we get x as 0.1
mgh=1/2mv^2+1/2mv^2+kx^2
since velocity of both the blocks will be the same
solving it we wll get v as 1.5

ur right

u see cant solve it but i know the concepts

let the weight of block a be M and that of b be m
Mgh>1/2kx^2
at least
Mg=kx

its out of my capability

sum no 61)
N+mg=mv^2/r
n>0
mv^2/r=mg at leat
thus v=rootrg

sum no 50)
sinc ethere is no ext. force acting the mechanichal energy will
i know the principe but i cant figure out at what elongation will the block break free

49)
if the block moves in a complete circle then the radius is 2l
therefore the work done against gravity is 2mgl
therefore 1/2mv^2=2mgl

therefore v-root 2gl

45) since there is no non-conservative forces
the maximum elongation
mgh=1/2kx^2
or the decrease in height is propotional t increase in the elongation
hieght decreased is x if the springs elongation is x
therefore
mgx=1/2kx^2

therefore x is 2mg/k

ok now i understood
thnx

could u pls expln the mathematics with the help of a diagram

PLS SOLVE IT

OH I DID NOT UNDERSTAND THE SUM
NEVERTHLEESS COULD U GICVE ME THE ANSWER
WITH MATHEMATICS

SSEE HCV SUM NO 51