goIIT: IIT JEE AIEEE CET WBJEE VITJEE BITSAT IIIT AICET Engineering Entrance Experts, Student Discussion Community, IIT JEE Preparation Online

thanks for your excellent reply.

acc. to eintein's theory photoelectric work function h

₁=h

₀ + kinetic energy

h

₁ is energy of incident light and h

0 is a photoelectric work function. So all the photns are not absorbed by any free electron.

hey guru what books do you refer?

x = x

x²= x²

x²- x²= x²- x²

(x+x) (x-x) = x (x-x)

x+x=x

if x=1

2 = 1

therefore maths proved wrong

hey guru just see that which one is giving proton or accepting a pair of electrons is acid and the one which is accepting a proton or donating a lone pair is a base

Hey ashish its too simple, Concentration of any solid, liquid or gas depends over its density and its molecular mass solids & pure liquids have these relation a constant so we do not consider them in our reactions rather we take their concentrations as unity.

If you feel that I am wrong somewhere then plz let me know afterall I m also a small kid

They say no. of arranging n distinct objects around a circle is (n-1)!

How do they say this?

Hey puneet bhaiya plz lend me some info about Circular Permutation!!

hey rajat just have alook at it:

ClO₃ ---------> ClO^- E= -0.54V **************** 1

ClO^- ----------> 1/2 Cl₂ E= - 0.45V ***************2

1/2 Cl₂ ----------> Cl^- E=0.17 V ***************3

ClO₃ ------------->Cl^-- E=?

eqn 1 + eqn 2 implies

ClO₃ ---------> 1/2 Cl₂ E= - 0.99V ***************4

1/2 Cl₂ ----------> Cl^- E=0.17 V ***************3

eqn 4 +eqn 3 implies

ClO₃ ---------> Cl^- E= -0.82 V

is this your answer ?

if any mistakes then plz let me know

is the answer 6.63*10^-5

Hey! here is your venturimeter:
It consist of 2 identical coaxial tubes A & C connected by a narrow coaxial tube B.Two vertical tubes D & E are mounted on the tubes A & B to measure pressure of the flowing liquid.
if a1,a2 are areas of cross section of A & B. V is volume of liquid flowing per sec then exp. is :
V=a1a2 [2hg/(a1^2-a2^2)]^1/2

hey it's too simple.
have a look at it:h=2s/R*density*g
R:RADIUS OF CURVATURE
THEREFORE hR=constant therfore liqud does not flow out
as h decreases R increases and surface becomes flat

will u give me a little hint I am very near to your answer

Thanks for your reply plz can you tell me something about u

i am trying to do it.let's communicate