As one cordinate is (sin60,0),and p lies withinn the triangle <60.

As another coordinate is (0,cos30),and p lies withinn the triangle

theta>30.

{Draw the figure after drawing x and y-axis, u will get the logic.}

I think the answer is  lies between 30 degrees and 60 degrees.

I am giving details in a few minutes.

 

 

Find the derivative of the polynomial w.r.t x. Equate the derivative to 0.

The value of x obtained, when being put in in the polynomial will give its max.(A<0)

or min. value(A>0).

After this, the graph can be drawn easily.

For ex;

y=2x^2+12x+16

Derivative=4x+12=0

which gives x=-3

On putting  x=-3 in

y=2x^2+12x+16, we get min. value of this polynomial.

which comes out to be -2.

Plzzz rate me if this was helpful.

Perin, I have answered ur question completely when u had asked it earlier.

U can look there to get the solution.

Plzzzzzzz rate me if my above answers are correct.

 

1) To find the kinetic energy, use the formula =h/mv and then calculate kinetic energy by 1/2mv².

 = 6.67 x 10^-10 = 6.63 x 10^-34

                                    ----------------------------------------

                            9.1 x 10^-31      x    v

 

which on simplification gives v=0.109 x 10⁷  m/s.

K.E. = 1/2mv²   where m = mass of electron

On putting the values and getting the answer in joule as 

5.4 x 10^-19    J , convert it into eV to get 3.38 eV.

 

2) Now,

    as K.E. = kZe²

                   ------

                    2r  

and P.E.= - kZe²  / r

we have P.E.= - 2 K.E.

 

Thus, P.E.= -6.78 eV.

 

3)       Wavenumber

      --------------------------    =   Z² {1- 1/ ²}

         Rydberg's constant

From this u will get Z=2.

 

Now, E= -13.6 Z²/N²  EV

 

Using this or rydberg's equation, wavelength of photon emitted during the shortest wavelength of transition from the excited state can be found out easily.

lim ( tan pi(x+2) - 2pi )/ (x+2)

 

lim tan pi(x+2) - tan 2pi/1+ tan2pi(tan pi(x+2))

As tan 2pi is zero,

 

lim  tan pi(x+2)   x   pi

       -------------------------

             pi(x+2)

Thus,    

(limit x tends to -2) (tan x)/(x+2) = pi

 

^g1)

 

1 molecule of NH3 has 1 proton each of 3 Hydrogen & 14 proton of 1 Nitrogen, so, total protons  = 17 per molecule

 

1 mole NH₃ is 17g.

We have 0.002 moles , i.e. ,therefore we have 6.022 x 10²³ x 0.002=12.044 x 10²⁰ molecules.

And  no. of protons=12.044 x 10²⁰ x 17

Mass of protons= 12.044 x 10²⁰ x 17 x 1.66 x 10^-24 g  {Becoz mass of a proton=1.66 x 10^-24 } 

 

which gives 0.034 g.

Plz rate me if correct.                    

Prove That:

sin²4x + cos²x = 2 sin4x +cos⁴x

Solve The equation:

3/2 sinx - cosx=cos²x

(sinx is multiplied by 3^1/2 , not 2)

A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10 L (at ntp) of this welding gas is found to weigh 11.6 g.

Calculate

1) empirical formula

2) molar mass of gas

3) molecular formula

(  Please give explanation of 1st and 3rd part)