the ans is 1.

after multiplying with ax in denominator we get

{6a[(rootx^2+ax+a^2)]  -  root(x^2+a^2)}/{6ax+2a^2-1/x-xe^1/x}

=take x common fm num. and denom.

=x^2{6a[root(1+a/x+(a/x)^2)]-root(1+(a/x)^2)/x^2{6a+2a^2/x-1/x^2-e^1/x}

=6a-1/6a-1=1(on applying x tends to infinity)

i am getting259(phy61,che98,mat100)in iitjee 2007

and 269(phy100,che87,mat82)in aieee 2007

please predict my ranks!!

my marks phy-61

chem-98

maths-100

total-259

good enough to get thro??

can ya teell me ma projected rank??

hi guys!me got

mat100

phy 61

chem98

tot259!!

will i be able to clear jee??

if so wt rank??

sir,

ihave procured

p-61

c-98

m-100

total 259(fiit key?

will i get thro?

of yes wt rank?