Messages posted by akhil@123.co.in

i think its answer is a and b.............

becoz.....low IE is responsible and due to emmisson spectrum it exhibits color...

may be correct...

oh yes DECODER also...very much thanx to u....

rates to ALL who posted answers to my question....... ans given in my boofk are:

b)

a)

b)

AGAIN THANKS TO PRANAV ,SAHARSHA,AKSHAY.......and every one

NO!!!!!!!!

Letf(x) =min{ x-[x] , -x-[x]}, -2<=x<=2 ;

g(x)=|2-|x-2|| ,-2<=x<=2

and h(x)=|sin x|/sinx,-2<=x<=2

and x not = 0.

on the basis of above information....

1)the no. of solution of the eqn..x²+[f(x)]²=1 is....{-1<=x<=1}

a)0 b)2 c)4 d)6

2) the rabge of f(x) ...

a) [0,0.5] b) [0,1] c)[0,2] d)none of these.

3) the sum of all the roots of the eqn g(x)-h(x)=0 is..{-2<=x<=2}

a)+ve b) -ve c)0 d)none of these..

4) The set of values of a such that eqn f(x)-a=0

a) a belongs to (0,0.5)

b)a belongs [0,0.5)

c)a belongs [0,1]

d) a belongs (0,1)

5) the value of integration of f(x)dx..{with limit -2 to 2} is

a)0 b) 1 c) 2 d) 8

HELP ME!

RATES ASSURED!

GIVE SOLUTIONS OR HINTS!

thanks bro..........

meet u with my next question........

find a and b.

rates assured...

i dont have answer of this question ...got from paper.

@ saharsha u mis took my question ...but a mindblowing solution

thanks......for allowin method..

remember log has base of 0.3

find domain

question ?

9.9/10

9.9/10

7/10......y sehwag.

answer given by saharsha is correct..........

{x+1}+2x=4[x+1]-6

{}=fractional part..[]=integral part...pls solvve..rates assured.

not bad...

nice.

very helpful....

nice1

nice1

nice!

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