Messages posted by nugorama@gmail.com

Finally a reason to login. :)

Dear Chulbul,

We KNOW you're frustrated with your college life/ marital life/ whatever.

We KNOW VIT sucks big time.

We've heard it over and over again, and now you sound more like a crying baby and less like a public-awareness-chap. Stop it.

Secondly, NO-ONE can predict the ranks, they just try to. With the changing patterns of a national-level-exam, its difficult for even the most experienced. And of all the geniuses, YOU took the job. Funny.

In a nutshell, your blabbering isnt at all useful. F^CK OFF.

Dear the-rest-of-you,

We know mods are a bit slow. This isnt facebook. Try ignoring idiots rather than replying to them and motivating them to crap some more. Also, refer good teachers and experienced friends for better results. I'm thankful to those who didnt and will not comment any further. Save fuel. ;)

Dear mods,

This isnt the first time. And this isnt the last time. I'm sorry but you've got to face the truth.

Moderators, we have a guest. :)

P(n) = 5^n - 5

= 5[5^(n-1) - 1]

Now, a^n - 1 is divisible by (a-1)

(as a^n - b^n is divisible by (a-b))

(Use: a^n - b^n = (a-b) (a^(n-1) + a^(n-2)b + a^(n-3)b^2 + ... a^(n-1-k)b^k ... + b^(n-1)) )

Hence, P(n) is divisible by (5-1) ie 4.

12 log(3) = 5.72545506

24 log(2) = 7.2247199

"Compare logs. :)"

First post dude. He's a 'new kid on the block'... Happens.

Relax. Let the ranks be declared.

Complete the question. And I doubt its -X axis.

Arihant.

Simple.

xyz = 1, this implies y = 1/xz ....(1)

y + 1/x = 29 ......(2)

1/xz + 1/x = 29

1/x( 1/z + 1 ) = 29......(3)

x + 1/z = 5, this implies 1/z = 5 -x

Put the value of 1/z in (3)

1/x ( 5 - x + 1) = 29

6 - x = 29x

30x = 6

x = 1/5

Put the value of x in (2)

y + 5 = 29

y = 24

Put the value of x and y in (1)

1/5.24.z = 1

z = 5/24

Hence, x = 1/5, y = 24 and z = 5/24

Now, z + 1/x = 5/24 + 5 = 125/24. Answer.

Was stuck with division by 3 part..nicely solved. :)

Nice answer.

Dont you think the first question is incomplete? It says nothing about the speed.

Used hit and trial. x = 3, lhs = rhs = 216.

5832 = 18^3

= ((3root2)^2)^3

= (3root2)^6

Hence log (base 3root2) 5832 = 6.

Answer.

GopaKumar HAS considered the area of the triangle: 1/2.base.height = 1/2.1.2.

Ofcourse, Varun.

Consider 2 odd functions f(x) and g(x).

Hence, f(-x) = - f(x) and g(-x) = - g(x)

f(-x)g(-x) = f(x)g(x) which makes their product an even function.

~~Thought of the day: Cloud nine gets all the publicity, but cloud eight actually is cheaper, less crowded, and has a better view.~~

Its a tricky one so I'm not sure if I'll end up with the correct answer.

Obviously, both the statements are correct. And at first glance, we dont see any significant relation between the two statements.

Just for the sake of it, rewrite f(x) = x^2 e^-x^2 sin lxl as f(x) = x.(x e^-x^2 sin lxl) ..

So, we have two odd functions now. And hence statement 2 is the correct explanation of statement 1.

My answer, (2).

24 log(2) = 7.2247199

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