Messages posted by radhika@rediff.in

ya!

the answer is 4.......

[x ]= GIF

the valve of above is...

a)2

b)4

c)8/3

d)none of these

wat is the graph of...........

|y|=sinx

and

|y|=|sinx|

ya it is(a)

no one solving............

no it is not 2 pi...

options are....

a)3(pi³)/4

b)3(pi²)/4

c)4(pi²)/3

d) 4(pi³)3

FIND PERIOD OF THIS FUNCTION>>>>>>>>>>>>>>>

rates...no doubt....

all 3 articles were good

"confidence"to his face.....

thax a lot!

assertion: f(x)is continious ,then |f(|x|)| is also continious.

reason: if |f(x)|<= |x|( where x belongs to R), then |f(x)| is continious at x=0.

RATES ASSURED!

stick to basics....

ya ..correct..

assertion:

reason: f(x) is a periodic function...

9/10........."saharsha" nice name....

good...questions...

thanx a lot!!!!!!!!!!

come on yaar!

f: R ---> R is a function such that

f(x)=x³+ x²f'(1)+xf'(2)+f'''(3)

for all x belongs to R..

then f(2)-f(1)= ........?

a)f(0)

b) -f(0)

c) f'(0)

d)-f'(0)

reply......

rates assured.....

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