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I have got the acknowledgement card from IIT-B. But you don't need to worry. You were supposed to be worried if the IIT-B site would have shown that your form has not been received. Since it is showing the result mentioned by you, that means that your application has reached there and has also cleared the hurdle, and has passed the required conditions. Acknowledgement card in only there to tell you that your applicaion has reached the respective IIT zone and they did not find anything lacking in it. So, if you don't receive it, it does not matter. Nobody is going to ask for it later. But it is given on the IIT-B website that if you don't receive your admit card, then you have to take your acknowledgement card along with two photographs, write your name, appl no etc on two A4 papers and then get the photos attested etc by the head of institution og school last attended, or by gazetted officer etc. For more info visit the IIT-B site FAQ section. But don't think about that. Everthing will take place nicely.
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With due respect, I did not say that ML Khanna is not a good book. It is a good book for building up your concepts and gaining confidence to go for the tougher problems from the other tougher books. But ultimately you have to do one more book after ML Khanna for tougher problems. This is my opinion. You may or may not agree. Since it appears that Shashank you are in 11 std, so you have the time to do it. So go for it boy. And frankly speaking, I am not an expert. I am also learning things like you are. What I felt, I have written that. Besides this, you can look forward to some more replies.
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According to me M L Khanna is a bit easier, and definitely a bit less than the IIT Level. Das Gupta Objective is AIEEE Level. I don't know about the new pattern Das Gupta and Subjective Das Gupta. For the first step towards JEE, you can try the above books along with AD Gupta. Then after getting a grip on these books, you can do TMH. For calculus, you can do I.A.Maron. Having named so many books, obviously it is not possible to do all of them. So i would advise you to any one of the above books, then finally do TMH. Plus you would also be having study material provided by your coaching classes (if you have joined any). If you haven't, then does not matter. Just do these good books, then you'll be fine. Instead of buying too many books, just concentrate on one or two good books, of the level of JEE. Some may differ from my opinion, but this is what I feel.
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I would say that TMH is the best. The problems given in TMH are of very good standard, much better than ML Khanna and all. If time permits, then you start with ML Khanna and then move on to TMH. Otherwise you can start off with TMH directly, if you have a good base (i.e. you are already capable of tackling books such as RD Sharma). The problems of TMH are not at all copied from ML Khanna and all. So, personally speaking I would recommend you to have TMH.
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I agree with Debarun that benzoic acid is more acidic than acetic acid. I have confirmed it from my notes and the literature of some famous books. As a result, I have corrected my mistake in my previous solution. So, benzoic acid is stronger acid than acetic acid.
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Benzoic acid is more acidic than acetic acid.
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Respected Aakash, In your reply you have said that the particle will move along the  y axis since the electric line of force is the equation of a circle, and hence the force on the particle will act towards the centre of the circle, whether it be +ve y axis or -ve y axis. So, then the answer should have been z=2, which is along y-axis. But unfortunately, no such option is given. Also, you have given the answer (d).
Can you please explain?
Please explain the complete solution. Everyone is cordially invited for their solutions.
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An electric line of force in the y-z plane is given by the equation  . A particle with unit positive charge initially at rest at the point y=0,z=2,in the y-z plane:
(a) will not move at all
(b) will move along z=0
(c) will move along a circular line of force.
(d) will move along the line y=2 Please give the explanation.
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An electric line of force in the y-z plane is given by the equation  . A particle with unit positive charge initially at rest at the point y=0,z=2,in the y-z plane:
a. will not move at all
b. will move along z=0
c. will move along a circular line of force.
d. will move along the line y=2
Please give the explanation.
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No more answers???? Someone please give the answer. Experts please help!!!!!
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How did you get the locus as x=a/2 ? Can you please explain. I have understood the rest of the solution.
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What about the rest of the options? Will they also be rational or not??????? If yes, why? If not, why not?
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Option (a) is correct. I am also sure of that. But I do not know whether the other options are correct or not. The answer given in the book is (a), (c) and (d). But I am confused whether (c) and (d) are correct or not. This is because the answer given in 30 Years IIT Question book is (a). This question came in IIT 1998 paper. Someone please clarify, giving proper explanation.
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MATCH THE FOLLOWING Locus of the mid-points of the intercepts between the coordinate axes by the lines passing through a fixed point (a,0)
| (i) does not intersect | (a) x-axis | | (ii) intersects | (b) y-axis | | (iii) is neither parallel nor perpendicular to | (c) y=x | Please give the explanation also.
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ONE OR MORE THAN ONE CHOICE CORRECT
If the vertices P,Q,R of a triangle PQR are rational points, which of the following points of the triangle PQR is/are always rational point(s)?
(a) centroid
(b) incentre
(c) circumcentre
(d) orthocentre
Please give the explanation also.
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Someone please give the correct solution.
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Logically, this structure seems to be correct. But it may or may not be correct. This is because here a single carbon atom is losing two molecules of water. So I just want to know that can a single carbon molecule lose two water molecules? And hence can the given structure be the correct answer? Please explain??????
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The adduct (P) is 
The answer given is (a). But I want to know that since Oxygen is more electronegative than Cl, how can the electrons shift in the direction of Cl???? 
The intermediate formed is a carbocation. Then the nucleophile chloride ion attacks on the secondary carbocation, thereby giving product (a). According to me the answer should be (b). Someone please explain with proper mechanism.
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