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the question must have options
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@AJ1991 what for you wanted rates?
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it means that A, B, C......K are assigned the integers 1,2,3...........11 arbitrarily.
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so easy yaar. the answer is 17!.16C12.12! / 4!5!2!3!4!4!
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for a triangle to be formed we need to have sum of any two sides to be greater than the third side. so we cancel out the combinations like 2,3,5; 2,3,6; 2,3,7; 2,4,6; 2,4,7; 2,5,7; 3,4,7 so the answer is 6C3 - 7 = 13.
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do it by contradiction. first of all the no. is not necessarily zero. next let us assume that we have the product as odd no. now for the six odd numbers we need to have six even numbers and for five even numbers we need to five odd numbers to make the product odd which is not possible as we need to have every factor to be odd. so the answer is (c) and the situation need just one even number to be even itself.
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After ditributing away three Rs.100 notes one is left along with other five notes. each of these notes have three choices. so the answer is 36
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it must be (c) always even
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the answer would be 5C4.4!.6! or 6C5.5!5! (both are 86400)
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what about the other two questions???
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the one for which the conjugate base comes out to be the most stable. generally the hydrogens attached to carbon are not acidic except for the alpha carbon w.r.t. carbonyl groups
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A = 60
B = 175
C = 66
D = 70
so, A-p; B-p,q,r; C-p; D-p
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