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solution sir??? maybe maybe maybe maybe maybe maybe

http://joigroup.freezoka.com/viewtopic.php?f=55&p=3368#p3368

x is not given Mr. Green

same prob posted by the legendary rushil Mr. Green

http://www.artofproblemsolving.com/Forum/viewtopic.php?t=42881 Smile

whatever!!

thanks!!

very nice website!!!

u should mention the source!

Is the question $\int \frac{\sqrt{1-\sin x}}{1+\cos x}.e^{\frac{-x}{2}} dx$ ??

if yes, then its very easy

$I = \int \frac{\sqrt{\sin^2 \frac{x}{2}+\cos^2 \frac{x}{2}-2\sin \frac{x}{2}\cos \frac{x}{2}}}{2 \cos^2 \frac{x}{2}}.e^{\frac{-x}{2}} dx$

$I = \int \frac{\sin \frac{x}{2} - \cos \frac{x}{2}}{2 \cos^2 \frac{x}{2}}.e^{\frac{-x}{2}} dx$

Strictly speaking, it should be $\mid \sin \frac{x}{2} - \cos \frac{x}{2} \mid$

$I =\frac{1}{2} \int (\tan \frac{x}{2}.\sec \frac{x}{2}- \sec \frac{x}{2}) . e^{\frac{-x}{2} dx$

which is equal to $e^{\frac{-x}{2}}. \sec \frac{x}{2} + c$