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Catalogs Discussion Forums -> Trignometry -> the number of real solutions of the eq -> Go to message
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sec^{-1}x= \frac{\pi}{2} - 2tan^{-1}x \\ \\<br/>x=cosec[2 tan^{-1}x] \\ \\<br/>=cosec [cosec ^{-1} (\frac{1+x^2}{2x}) \\ \\<br/>x=\frac{1+x^2}{2x} \\ \\<br/>x^2=1 \\ \\<br/>, \mbox{hence 2 solns }-> +1, -1

Catalogs Discussion Forums -> Analytical Geometry -> Straight lines -> Go to message
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4)\mbox{The point of intersection as calculated in qn 1 is}-> \\ \\<br/>\frac{ab}{a+b} , \frac{ab}{a+b}  \\ \\<br/>\mbox{Putting it in the eqn , we get }-> \\ \\<br/>\frac{1}{c} + \frac{1}{d}=\frac{a+b}{ab}=\frac{1}{a}+\frac{1}{b}

Catalogs Discussion Forums -> Analytical Geometry -> Straight lines -> Go to message
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3)\mbox{The equation can be rewritten as }-> \\ \\<br/>(x+y-1) + \frac{q}{p}(2x - 3y + 1)=0 .........or \\ \\<br/>L_1 + \lambda L_2 = 0 .....\\ \\<br/>\mbox{Hence it passes through point of intersection of }-> \\ \\<br/>x+y-1=0 , \ and \ ,2x - 3y + 1=0 \\ \\<br/>which \ is \ \\ \\<br/>\frac{2}{5},\frac{3}{5}

Catalogs Discussion Forums -> Analytical Geometry -> Straight lines -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
11 replies   

1) \mbox{Point of intersection = } [\frac{ab}{a+b},\frac{ab}{a+b}] \\ \\<br/>\mbox{Let the equation of line be }->y=mx + c \\ \\<br/>\mbox{Now since it passes through} \frac{ab}{a+b},\frac{ab}{a+b} ,\mbox{ we get relation as }-> \\ \\<br/>c = \frac{[1-m]ab}{a+b} \\ \\<br/>Also , A -> \frac{-c}{m}, 0 \\ \\<br/>B -> 0, c \\ \\<br/>Mid-Point -> x=\frac{-c}{2m} , y=\frac{c}{2} \\ \\<br/>\mbox{which implies }m = \frac{-y}{x} \\ \\<br/>Hence -> \\ \\<br/>y=\frac{c}{2}=\frac{[1-m]ab}{2(a+b)}=\frac{[x+y]ab}{2x(a+b)}\\ \\<br/>or ->\\ \\<br/>\mbox{2xy(a+b)=ab(x+y)}

Community shelf Community shelf -> The JEE Guide -> Go to message
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40 replies   
6]" Keep a positive attitude. Approach new topics with interest, not with an another-topic-to-mug attitude. Do some research on wikipedia, try to find applications in day-to-day life. This will help create interest in the topic and improve your understanding as an engineer."

...........that seems the most important thing !!!Anyways its nice that u wrote such an article with everything coming straight out of experience :)
Catalogs Discussion Forums -> Lounge -> RATE THE FUNNY PIC -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
69 replies   

bachna ae haseenon http://www.unity.i8i.co.uk/forum/images/smiley_lol.gif


 


Catalogs Discussion Forums -> Magnetism -> Doubt :( -> Go to message
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5 replies   



www.comsol.com/showroom/gallery/15.php



en.wikipedia.org/wiki/Helmholtz_coil


physicsx.pr.erau.edu/HelmholtzCoils/index.html



Catalogs Discussion Forums -> Magnetism -> Doubt :( -> Go to message
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Verify that on the axis of helmholtz coil , midway between the coils , the first 3 derivatives of B with respect to x vanish.


 


(This is the complete qn)

Catalogs Discussion Forums -> Lounge -> GAME:RATE THE PIC -> Go to message
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2616 replies   
9.1 , its different :D

(i really want to know what comments this pic evokes :D :D )
Catalogs Discussion Forums -> Mechanics -> what do u think ? -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
45 replies   

So , the conclusion i come to is that ,the answer is no (provided the height is till which the helicopter is taken to is neglegible compared to radius , which even though not given in the question seems a reasonable assumption )


 


http://writeontheinternet.files.wordpress.com/2007/09/superman.jpg

Catalogs Discussion Forums -> Mechanics -> what do u think ? -> Go to message
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I am a superman [:D] . I lift a helicopter from earth and go a certain height above the earth . Then i wait for earth to rotate , and soon america comes right below me and i come down . Hence i reach america  .


Is this possible ??


 


Assume that america does come under me for sure , wherever be my original position and also assume that i have a lot of time [:)]

Catalogs Discussion Forums -> Mechanics -> rotational motion -> Go to message
This Post 15 points    (Olaaa!! Perrrfect answer.   in 3 votes )   [?]
5 replies   

The theorem states that when 2 non parallel velocities are given at any 2 points then , draw perpendiculars from them and the point of intersection of these perpendiculars gives us the location of INSTANTANEOUS CENTRE of zero velocity )IC . 


It can be followed in the figure given below


Now we can proceed by conserving energy as told above and using the fact that


V of COM = w * l /2 [cos theta]

Catalogs Discussion Forums -> Mechanics -> Lets c who answers this one,,,,,,,,,,,,, -> Go to message
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2 replies   
http://www.goiit.com/posts/list/mechanics-try-this-nice-one-from-mechanics-50034.htm
Catalogs Discussion Forums -> Coaching Institutes & Course Material -> How new IITJEE pattern is slowly killing kota? -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
49 replies   
To what extent can people go for pure advertisement !!!!

Anyways , i think rydbyrd is getting the attention he wants from us !!!!
(by saying anything literally anything :D )
Catalogs Discussion Forums -> Electricity -> Q.A thin, metallic spherical shell contains a charge Q on it -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
3 replies   

1) d) as charge is inside the shell and field inside the shell is 0





2)Since Force is 0 ,force applied by shell would be in the opposite direction to what  the charge q1 is applying force on q,ie, if q1 is on right of q then it will apply a repulsive force on q towards left and to balance it the shell would apply the force towards right .However since u have not mentioned the location of q1 exactly ,its impossible to predict the answer

 
 
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