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Multiplying above and below by , we get

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A uniform wire is bent in the form of a rectangular loops of sides 'a' and 'b' .Calculate field at the center if thecurrent in sides is I amp.

ANSWER=

Arihant

Find the oxidation number and co-ordination number .

Please explain the method to find in this compound

Due to editor, it is disroupted

Anyone please reply me

Write it as

(Multiplying above and below by 2)

Write it as

now

+

Now in the first integral put (cosx+sinx)=t and in the second one put (cosx-sinx)=z and then apply some special integral to get the result

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A long straight wire passes through the holes at the

opposite corners of a regular hexagon of side 10

cm.Calculate the magnetic field induction at the

point A,B,C and D due to small element of length 0.02

cm of the wire situated at the corner of the

hexagon .The current in the wire is 200 ampere.

slaping gonik because his picture is of thief and i am a police.....

Great job.. sir ..

Thank u

No one in goiit to solve this one......

Thank u and please solve my other integral question in the integration forum......

Please explain the steps................rates assured

ur answer is correct

But please explain the steps . rates assured