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Particle of charge q is brought from A to B, following the path as a sinusoidal function, and then find the work done in doing so? The point ?A?, is ?r?, distance from the infinitely long linear body given in figure.Write with the correct explanation for the answer.
Please find the figure in the attached file.

Particle of charge q is brought from A to B, following the path as a sinusoidal function, and then find the work done in doing so? The point ?A?, is ?r?, distance from the infinitely long linear body given in figure.
Write with the correct explanation for the answer.

Please find the figure is in the attached file.

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Its a great thing thanks for sharing it.

Don't waste your nickels in stupid NCERT questions.

Ya

If the half of the range is equal to the max^mheight the its trajectory will be a semi-circle.

1/2(R) =H

or, (u²sin2x)2g = u²sin²x/2g

sin2x= sin²x

2cosx = sinx

tanx= 2

x= tan^-1(2)

ANS

Don't forget to give a solute.

Hi

You should try to be aster of Complex No, Rotational Motion, Coordinate.

Keep confidence in you, being confident you can crack any exam

All the Best

May God Bless u with IITB.

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Hi

Look this is that case when half of the range is equal to the max^mheight, therefore forms a semi-circle

(u²sin2x)/2g = (u²sin²x)/2g

sin2x= sin²x

2cosx=sinx

or, x=tan^-1(2) -Ans

_{Find the value of :}

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^{[1/0 ]} _{[j=0 ]}

^{[1/0 ]} _{[k=0 ]}

^{[1/0 ]} 1/(3ⁱ.3^j.3^k) [ i

j

k]

1.)

Let z₁&z₂be any two arbitrary complex nos, then prove that :

| z₁+ z₂| >= 1/2(|z₁| +|z₂|) | z₁/|z₁| + z₂/|z₂| |

2.)

If sin log (iⁱ) = a +ib. find a and b. Hence find cos(log iⁱ).

Ans. a= -1, b= 0, 0

I think you try them for having a strong base about the topic,
but now IIT is fully objective, thats why u should do more objective probs

_{Find the value of :}

_{[i=0 ]}

^{[1/0 ]} _{[j=0 ]}

^{[1/0 ]} _{[k=0 ]}

^{[1/0 ]} 1/(3ⁱ.3^j.3^k) [ i

j

k]