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chennai superkings

hey see this

given a+b+c=0

therefore

substituting in given exprssn

ax^2+bx+(-a-b)

=a(x^2-1)+b(x-1)=0

taking( x-1) common

(x-1)(ax+a+b)=0

that implies

x=1 or ax=-(a+b )

=ax=c (given a+b+c=0)

therefore x=c/a

therfore answer is 1, c/a

correct if i am wrong!!

Uday is exactly correct
answer is C

expanding 1+tanx/1-tanx

we get

cosx+sinx/cosx-sinx

d/dx of cosx -sinx is -(sinx+cosx)

so let

cosx-sinx=t

then we get

$\int$ -dt/t

= -logt

=-log(cosx-sinx)

correct if i am wrong!!!

is the answer -log(cosx-sinx)??

yes the answer is zero since sin(1/0)is some finite value

My support is for Deccan chargers
they will surely win!!!!!!!!!!!!!!

MANY MANY HAPPY RETURNS OF THE DAY!!!!!!

TRANSLTR is correct
Fe is catalyst Mo is promoter

anyone!!!!!!!!!

A neutron collides head on with a stationary hydrogen atom in ground state.Which of the following statements is /are true??

a)if kinetic energy of the neutron is less than 13.6eV , collision must be elastic.

b)if kinetic energy of the neutron is less than 13.6eV, collision may be inelastic.

c)Inelastic collision may take place when initial kinetic energy of neutron is greater than 13.6eV.

d)perfectly inelastic collision can not take place.

plz explain!!

_{[ x]}

_{[ 0] -} f(x) =_{[ x]}

_{[ 0]} f(0-h)=

_{= [h ]}

_{[ 0]} e^-1/h-1 /e^-1/h+1 =_{[ h]}

_{[0 ]} (1/e^1/h-1) /(1/e^1/h+1) = 0-1/0+1 = -1

RHL

_{[ x][0 ]} f(x) =_{[h ][0 ]} f(0+h)

₌_{[h ]}

_{[ 0]} 1-1/e^1/h/1+1/e^1/h =1 {taking e^1/hcommon frm den and numerator}

therefore limit doesnot exist

yes the relation is true for all the positive values of two or more numbers(and also they must be unequal)

but the answer is b