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see, this is the point where most of the people are wrong because the main condition for aldol is not alpha-hydrogen but the acidity of the alpha hydrogen.

If you know the mechanism of aldol condensation then you'll know that in 1st step, the alpha hydrogen is withdrawn creating a carbanion which attacks on other molecules to proceed for aldol. As dilute NaOH is being used here & the alpha hydrogen is not acidic (in this question, due the presence of two methyl groups the alpha hydrogen will not be acidic) then OH^- ion will not be able to extract the alpha hydrogen & so, there will be no aldol. therefore, it will go for canizzaro....

In this question, A VERY STRONG BASE is required for aldol which against all odds can extract the alpha hydrogen...

i hope you get the concept...

apply the canizzaro reaction in this case & you'll get the answer....

i applied canizzaro due very low acidity of the alpha-hydrogen....

i hope you'll be able to do it...

i'm just guessin' on this. since considerable amount has the chemical has fallen so, i think the rate should increase..
am i correct?

i'm attaching the pic of the possible ans. i could think of.. there's a high chance that it could be incorrect but do hav a look....

see the image..

i think its in hydrogen bonding...

maybe hydroden due to very small size & no intermolecular force of attraction...

i think the answer is b)
the formula i used here is Cp/Cv = 1 + 2/f where f is the degree of freedom & degree of freedom for a diatomic gas is 5 (i guess...)

i guess (b) coz' aldehydes are quite reactive in nature towards nucleophilic attack.

as far as i know, the concentration of only pure solids can be ignored coz' in equlibrium, the concentration of solid substances is taken to be 1 .

see man, when P.D. is applied, then irrespective of the energy or velocity electrons are having , they align & move in a particular direction. in creating this motion(towards a particular direction), the electrons undergo multiple collision losing energy but due to P.D., they regain that energy & keep moving.

now, when there is no P.D., then when collisions occurs, the loss of energy of one electron is the gain in energy of the other electron, so, the total energy remains constant, so there is no temperature change...

plz correct me if i'm wrong....

as far as i know, nitrogen has a lone pair which can be kept in either sp3 hybrid orbital or in p ortbital if sp2 hybrid. so, when there is scope for resonance, the hybridisation of nitrogen is sp2 for better stabilisation of product. so, pyrrole is aromatic.

hey jatin, the angle theta used is the half angle of the apex, i think that's where you think there could be some mistake...

plz correct me if i'm wrong...

i think you should try "solomon & fryhle"..

see man, many people around me had this problem, but i never encountered such problem coz' the application runs in my internet explorer without any hassle.
one thing you can do is that install internet explorer 7 if you hav version 6.

tell me if it works..