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i think the answer is every $(6k -3)$ th derivative where $k$ = 1,2,3...
i.e. 3rd, 9th, 15th and so on..

no offence meant to any1, but is this site called goiit.com or gocbseboardexam.com?!

if you dont get it by reasoning (hsbhatt sir's method), then i suggest u do it by rigorous solving by using sin^-1x + sin^-1y = sin^-1[x^{[ ]}

(1-y²) + y^{[ ]}

(1 - x²) ]

though that method is extremely mundane

this may help u :)

2 metres.
simple constraint eqns for the strings.

refer here for further details

yes.. to put it bluntly, you cant differentiate it because the function is not continuous..

ganesha1991, how can the answer be independent of 'l'??

anyway, i think the answer is $\frac {2v +/- \sqrt {4v^2 - 4 \mu gl}}{\mu g}$

EDIT: its 2 v (plus or minus) root of....

your first line itself is wrong mate.. geostationary satellites revolve ONLY around the equator

after substituting x^2 = t, since the degree of numerator and denominator are same, then this can be written as

1 + A/(t+3) + B/(t-5) = (t+1)(t+4)/(t+3)(t-5)

is there any proper method to prove 2x-y - 1 anyway??

the basic idea behind electrostatic shielding is that, the electric FIELD inside a cavity of a metallic shell is 0
because of this, even when the shell is placed in some field, the electric field inside the shell = 0 and hence, any equipment (which may get damaged due to electric field) will NOT get damaged..
:)

the formula is:

C(specific heat) = $\frac {R}{gamma -1} + \frac {R}{1-n}$

Re:gud question-rates for satisfactory ans-

yes.. i shouldve explained that..
see after colliding with the stationary wall, the distance between the ball and the moving wall is
d - d(1-e)/(1+e)

wait... ill draw a diag and post it....