yes the electric field due to a conducting cone can be found if the electric field is perpendicular to its base(circle)

then =E.r²(area of base circle)

E=/r²

hope u got it.

hey man jab h0-to e ke power mein infinity aayega aur 1/infinity is 0

but jab h is 0+ toh e ke power mein -infinity aayega which means 1/(e)^infinity which is zero.

hope u got it.......

is the ans 153.

tell me if i m right then i will explain

we know that in a biquadratic eqn.

since all roots r real by descartes rules of signs

a⁵+b⁵+c⁵+d⁵=5pq in the general eqn. of 4th degree where a,b,c,d r the roots.

a⁵+b⁵+c⁵+d⁵=-105

hope u got it..

yes spidey u r right

then I would also go with allamraju that there is no such a.

thanx hsbhatt sir

plz give us some more tips like this.

i m not confident still i m trying

IIxI-4I=a has only one soln is given

we know that it can always have 2 values of x for 1 a one +ve and 1 -ve.

but as it is given to have 1 soln and not 2

therefore x=0

putiing x=0 we get

a=4

tell me if i m right.

hey dude it is easy

3⁹+3¹²+3¹⁵+3ⁿ=a³ where a  

taking log both sides

9log3+12log3+15log3+nlog3=3loga

3log3+4log3+5log3+n/3log3=loga

log(3³ x 3⁴ x 3⁵  x 3^n/3)=loga

taking antilog

3^12+n/3=a

therefore for a to be a perfect cube n should be a multiple of 9.

smallest n=9.

hope u got it.........

2nd ques

from where u get such ques man?

Tell me if I m going inthe right dir.

As I see p(x²)=(p(x))² is possible only when x=0 and equating we get

a₀ =a₀²  which gives a₀=0 or a₀=1.

it is also possible when x=1and on equating we get

(a₀+a₁+.......+a_n)=(a₀+......+a_n)²

which again gives  (a₀+ .......+a_n)=0 or (a₀+.........+a_n)=1.

I dont think so man!

hey hrishabhsharma ur proof is is wrong as well as nonsense when u have taken the square root u have to take the -ve one otherwise will will be getting such absurd results all ur life.

hey phayana man it is clearly given inthe ques that a_n#0.

Find all the complex numbers z such that

(3z+1)(4z+1)(6z+1)(12z+1)=2.

hey sandeepramesh I m very sorry for my misbehavior.No matter if our thoughts r not matching in this question but v r good friends.

Plz try man111 and my question.

in (1-1/73)⁷² will u not get 72.(1/73) as 2nd  term in the expansion taking 72 common from 72C36 and this we get the desired result.

at least put a liitle stress on ur brain man.