Hello ashish,
See,in case of an acid catalysed hydrolysiation the catalyst present in the solution is H3O+,in this case the ion gets split into more stable H2O and H+,now......the ester gets protonated and forms:
R-C(+)-(OH)(OR") and H2O in the solution,since in solution we dont account for the concentration of water so the reaction is dependent just upon the cocentration of the above mentioned cationic ester,so follows a first order kinetics.
Now,in case of a base catalysed reaction, teh ion present for catalysation is (OH-),now due to temporary shift of shared pair of e- that creates a temp + charge on C atom hence the hydroxyl ion attaches itself to the carbon atom therby creating:
R-C(O-)(OH)(OR"),along with OH- ion in the solution,hence the reaction depends upon the concentration of both the molecules,so it follows a SECOND ORDER KINCETICS.
Hope u find ur query answered.