Messages posted by srikrishna90909@gmail.com

There are no images to see

So there is something mistake in your question or the options given

First ( 1-i ) = 2^1/2( cos(-pie/4) + i sin(-pie/4) )

Now its whole power x = 2

The modulus of the complex number inside the bracket = 1

To equality to exist its modulus should be same on both sides.

to get equal modulus the value of x should be 2.

But if it is two we can see that LHS is imaginary, so x can't be 2.

therefore no of integral solutions of is 0 ( zero )

you may get if you have ST reservation

What to solve

which you previously had was good

your name was ....pagal guy.... comesback previously,i think so.i am telling about the picture of joker from dark night

why did you change your picture and name,joker suits your name well

very nice joke bit i think you are insulting gujraties

its what i expected

very nice timing

nice,very intelligent

Its a good doudt,i have never heard

very nice yar

this the best i have ever heard

its extraordinary

I have never heard better articles than this

Its very useful,thanks.I dont know how to caluculate till now.

Its around 175 as the analyzers and institutions say.

The paper seemed easy after exam but during exam it was difficult as the first paper was lengthy.292 is a good score and you expect a rank around 500.

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