Hello everyone!
If y = (sinx)cosx + (cosx)sinx, prove that
dy/dx = (sinx)cosx . [cotx cosx ? sinx (log sinx)] + (cosx)sinx. [cosx (log cosx) ? sinx tanx]
(CBSE 2004C)
The answer that I got was
dy/dx = [(sinx)cosx. (cosx)sinx] [cotx cosx ? sinx (logsinx) + cosx (log cosx) ? sinx tanx]
Kindly explain why I am getting it different. I?ll be grateful to you.
Thanks!
With regards
Ashish