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get download accelarator plus from speedbit.com

how 44N=4.4kg

take RC Mukherjee's Chemical Calculations made easy or P Bahadur
and ML Khanna for maths

u have enough books but i recommend u to buy ncert books instead of downloading them bcoz they are very useful and u can also have solution of concepts of physics but refer to it only after trying a question atleast 10 times

loops are statements in C++ to perform a specific task till the given
condition is satisfied

e.g
int x=1;
while(x<10)
{ cout<<"\n inside while";
i++}
will display 'inside while' till the value of x reaches 10 and then it will
go the next statement

other loops are for loop and do while loop

there is no min age but there is max age limit.

you get practice on

1) entrance123.com

2)hellochampion.com

3)entrancepractice.com

after finding double derivative put the value of x , if value is

negative you will get minima by putting the value of x in first derivative , maxima if value is positive

there wiil be no force if radius is very small & if radius is large
then take q/2 charge on each and use coulomb's law

either apply L Hospitals rule or use the formula

f(x)*g(x)= x->0 e^(g(x)*[f(x)-1]) when f(x)=1
and
e^[g(x)ln(f(x))] when f(x)!=1

here f(x)=1 so apply the formula & get the answer,remember in such questions the answer will always be in terms of e.

An n-digit numbers is a positive number with exactly n-digits.Nine hundred distinct n-digits numbers are to be formedusing only the three digits 2, 5 & 7. The smallest value for which this is possible is

a)4 b)8 c)10 d)3

T he answer is b as the total charge on the compund must be 0.

take x^y=u

e^(x-y)=v

both are equal so du/dx=dv/dx

find du/dx & dv/dx separately by taking log and equate them,take dy/dx on one side .this is your answer.

log u=logx^y

differentiate both sides

log u=ylogx

(1/u)du/dx=(dy/dx)logx + y/x

du/dx= [ (dy/dx)logx + y/x]x^y ,bringing u this side and keeping its value

now finding dv/dx

logv=(x-y)loge

(1/v)dv/dx=(1-dy/dx)(1/e)

dv/dx=[(1-dy/dx)(1/e)]e^(x-y)

put

du/dx = dv/dx

and get the answer

a better formula is H=SA+1/2(G-V-C) ,where SA is the no. of surrounding atoms, G is the no. of valence electrons in ground state, V is the valency of the atom & C is the the charge on molecule remember when there is negative charge on the molecule -C becomes positive & vice versa.for H=2,3,4,5,6,7 hybridization is sp2,sp3,sp3(dsp2 for complexes),sp3d,sp3d2 & sp3d3 respectively.This method is less time taking but can sometimes be wrong for complexes so the best method is H=no. of sigma bonds + lone pairs, when odd no. of eletrons are left in the valence shell then the single electron left should be taken a lone pair.