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Catalogs Discussion Forums -> Counselling Zone -> help -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
1 replies   
I think you should figure out topics you are weak in and than start revising them again ..
Also you should go through what has been taught in your coaching classes along with some new problems everyday .....
 
Please try to understand that you should be clear with theoritical portions before you start attempting various problems from various sources.
 
Once you are done with what i have suggested then you start solving test papers .. this generally gives a lot of confidence .. it gave me when i did my preparation ...
 
I hope my reply helps u ......... cheers
Catalogs Discussion Forums -> Counselling Zone -> My problem in preparing!!!!! -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
1 replies   
hii
First of all never lose hope ...... no one around is extraordinary ..
 
The phase you are going through is a very common one .. I went through it when i was preparing ... I remember it clearly that when I was in std 12th , I did faced problems like this ...
But then I did not lost hope and kept working hard ... n results spoke for themselves ... so just one advice .. keep working ..
 
God shall help u in suceeding
 
cheers
Catalogs Discussion Forums -> Differential Calculus -> limits -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
2 replies   
Open the series of cosx ex and e-x by power series method .....
 
Now use two concepts .. these are to be used in general while solving such questions
 
First the limit has to exist so the constant and coefficeint with x have to be zero since we have xsinx in the denominator ...
 
Second the coefficent of x2 term should give the limit .....
 
I hope this helps .. reply back to this post if things are not clear ..
 
cheers !!!
Catalogs Discussion Forums -> Algebra -> matematics/matrix -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
1 replies   
Let the two parts be x and y ..
 
So we have two equations
 
                       x + y = 30000
 
   and            0.09x + 0.11y = 3060
 
  Now write these equations as a matrix and we are done !!!
 
  cheers
Catalogs Discussion Forums -> Coaching Institutes & Course Material -> PLz answer my queries -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
2 replies   
Well both Delhi and Kota are good places to do JEE preparation. Both places have many good coaching institutes. However what matters is the fact that u do hard work .. okay ..

Well the study material of Brilliant is better however the classroom coaching of Vidyamandir is better ..

Again such things are perceptions that a individual has .. all depends as to what u like ...
Also I will suggest that once u join the coaching institute then study material that those suggest you to do so that there is a better coordination between you and your classes ...

cheers
Catalogs Discussion Forums -> Trignometry -> trigo [admin]: question to find range of theta -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
7 replies   
Well yes this is correct !!
If u want to find the range then this is also fine ... all depends on what the question demands !!
Catalogs Discussion Forums -> Trignometry -> trigo [admin]: question to find range of theta -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
7 replies   
This answer seems to be perfecto !!!  Gr8 work done !! 
Catalogs Discussion Forums -> Differential Calculus -> signum function -> Go to message
This Post 10 points    (Olaaa!! Perrrfect answer.   in 2 votes )   [?]
2 replies   
The books which represent sgn(x) as mod(x)/x have defined it wrong. The actual definition is as follows :
 
                    sgn(x) =  mod(x)/x   when x  0
                            
                              =  0              when x = 0
 
Now the thing should be hopefully clear ......
 
Cheers
 
 
Catalogs Discussion Forums -> Counselling Zone -> books -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
1 replies   
It is okay dear ... the syllabus for iit do not chnage much .... or let me put it this way that even if it changes the books remain the same ... a new edition of M.L. khanna wud just have a new cover and nothing more than that .. so u can use the book u have purchased and there is no need to worry about ...
 
cheers
 
Catalogs Discussion Forums -> Algebra -> permutation nd combination -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
10 replies   
Gr8 answer ... rahul gr8 work done ..
cheers
 
Catalogs Discussion Forums -> Differential Calculus -> calculus -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
4 replies   
hiiii
All the above suggested solutions are valid ..
See the key point is that u try to understand the concepts .. use some book say Arihant's book and start going through the theory of one chapter, once u know the theory then start solving problems ... going from easy to hard level .
 
While u solve problems focus on the concepts rather than the craming of way to solve the problems ... gradually u will start understanding the topics .. n u will not face any problem ..
 
Keep confidence in urself ... cheerooo
 
Catalogs Discussion Forums -> Integral Calculus -> indefinite integration -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
1 replies   
Put cos 2x = 1 / t

So, dx = dt / ( 2t2 . sin 2x)

so, cos2x/sinx = dt / ( 2t2 . 2sin2x) * t * cosx
                        
                         = dt / 2 * t(t-1) t+1

 Now put t + 1 = p2   

 So,  cos2x/sinx  = 2* dp / (p2 - 1)*( p2 - 2 )

                            =
2* dp / ( p2 - 2 ) - 2* dp / ( p2 - 1 )

Now these integrals can be easily intergated and thus we are done by resubstituting the values  of p.

Cheers !!!!!!!!!!!!
Catalogs Discussion Forums -> Differential Calculus -> differential calculus doubts -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
15 replies   
y = log10 x + log x 10 + log x x + log10 10
  =  logex / loge10 + loge10/logex + 1 + 1
 
dy/dx = 1 / (x * loge10) - loge10/((logex)2 * x) + 0
              =
1 / (x * loge10) - loge10/((logex)2 * x)

cheers !!!!!

Catalogs Discussion Forums -> Mechanics -> physics -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
2 replies   
Correct answer .... well done !!!
 
 
Catalogs Discussion Forums -> Mechanics -> work power energy -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
3 replies   
The answer is C since we do not know that the force is applied in which direction and what is the direction of the displacement.
 
Note that the work done if F.d !!!!
 
cheers
 
 
 
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