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Catalogs Discussion Forums -> Differential Calculus -> limits -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
Open the series of cosx ex and e-x by power series method .....
 
Now use two concepts .. these are to be used in general while solving such questions
 
First the limit has to exist so the constant and coefficeint with x have to be zero since we have xsinx in the denominator ...
 
Second the coefficent of x2 term should give the limit .....
 
I hope this helps .. reply back to this post if things are not clear ..
 
cheers !!!
Catalogs Discussion Forums -> Algebra -> matematics/matrix -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Let the two parts be x and y ..
 
So we have two equations
 
                       x + y = 30000
 
   and            0.09x + 0.11y = 3060
 
  Now write these equations as a matrix and we are done !!!
 
  cheers
Catalogs Discussion Forums -> Coaching Institutes & Course Material -> PLz answer my queries -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
Well both Delhi and Kota are good places to do JEE preparation. Both places have many good coaching institutes. However what matters is the fact that u do hard work .. okay ..

Well the study material of Brilliant is better however the classroom coaching of Vidyamandir is better ..

Again such things are perceptions that a individual has .. all depends as to what u like ...
Also I will suggest that once u join the coaching institute then study material that those suggest you to do so that there is a better coordination between you and your classes ...

cheers
Catalogs Discussion Forums -> Trignometry -> trigo [admin]: question to find range of theta -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
Well yes this is correct !!
If u want to find the range then this is also fine ... all depends on what the question demands !!
Catalogs Discussion Forums -> Trignometry -> trigo [admin]: question to find range of theta -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
This answer seems to be perfecto !!!  Gr8 work done !! 
Catalogs Discussion Forums -> Differential Calculus -> signum function -> Go to message
This Post 10 points    (Olaaa!! Perrrfect answer.   in 2 votes )   [?]
The books which represent sgn(x) as mod(x)/x have defined it wrong. The actual definition is as follows :
 
                    sgn(x) =  mod(x)/x   when x  0
                            
                              =  0              when x = 0
 
Now the thing should be hopefully clear ......
 
Cheers
 
 
Catalogs Discussion Forums -> Counselling Zone -> books -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
It is okay dear ... the syllabus for iit do not chnage much .... or let me put it this way that even if it changes the books remain the same ... a new edition of M.L. khanna wud just have a new cover and nothing more than that .. so u can use the book u have purchased and there is no need to worry about ...
 
cheers
 
Catalogs Discussion Forums -> Algebra -> permutation nd combination -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Gr8 answer ... rahul gr8 work done ..
cheers
 
Catalogs Discussion Forums -> Differential Calculus -> calculus -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
hiiii
All the above suggested solutions are valid ..
See the key point is that u try to understand the concepts .. use some book say Arihant's book and start going through the theory of one chapter, once u know the theory then start solving problems ... going from easy to hard level .
 
While u solve problems focus on the concepts rather than the craming of way to solve the problems ... gradually u will start understanding the topics .. n u will not face any problem ..
 
Keep confidence in urself ... cheerooo
 
Catalogs Discussion Forums -> Integral Calculus -> indefinite integration -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Put cos 2x = 1 / t

So, dx = dt / ( 2t2 . sin 2x)

so, cos2x/sinx = dt / ( 2t2 . 2sin2x) * t * cosx
                        
                         = dt / 2 * t(t-1) t+1

 Now put t + 1 = p2   

 So,  cos2x/sinx  = 2* dp / (p2 - 1)*( p2 - 2 )

                            =
2* dp / ( p2 - 2 ) - 2* dp / ( p2 - 1 )

Now these integrals can be easily intergated and thus we are done by resubstituting the values  of p.

Cheers !!!!!!!!!!!!
Catalogs Discussion Forums -> Differential Calculus -> differential calculus doubts -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
y = log10 x + log x 10 + log x x + log10 10
  =  logex / loge10 + loge10/logex + 1 + 1
 
dy/dx = 1 / (x * loge10) - loge10/((logex)2 * x) + 0
              =
1 / (x * loge10) - loge10/((logex)2 * x)

cheers !!!!!

Catalogs Discussion Forums -> Mechanics -> physics -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Correct answer .... well done !!!
 
 
Catalogs Discussion Forums -> Mechanics -> work power energy -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
The answer is C since we do not know that the force is applied in which direction and what is the direction of the displacement.
 
Note that the work done if F.d !!!!
 
cheers
 
Catalogs Discussion Forums -> Algebra -> trigo question -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Absolutely correct answer !!!! good work !!!!
Catalogs Discussion Forums -> Algebra -> permutation and combination -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Thank god u got it ........
Catalogs Discussion Forums -> Algebra -> permutation and combination -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
Ooooooops hmm how do I explain ?? hehe ... try to take a simple example let us suppose the word in LAMA and we need to make 2 letter words from that. OKAY ??
 
So let us see ... by using the previous approach
 
We will find coefficeint of x2 in the expression
    2! (1 + x)2(1 + x + x2/2)
   
    So we find coefficeint of x2 in ( 1 + x2 + 2.x).(1 + x + x2/2)
 
    The terms corresponding to x2 are 2! ( 1 + 2.1 + 1/2)x2
    which is 7.
 
     Now see the normal way the two letter words can be 
AA, AL, AM, LA, LM, MA, ML
 
which are 7 in number so the approach works okay??
 
The expression will change if u make 5 letter words .. in this case u will replace 4! by 5! and find coefficiet of x^5.
 
okay ... cheers
Catalogs Discussion Forums -> Algebra -> permutation and combination -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
okay let me explain ... first of all do not use that word SIR .. just a kid like u ... may made it earlier to IIT thats it . ok
 
Now about the approach .. see the letter E can appear in a four letter word for one , two or three times.. OKay ?? Now if the letter E appears 3 times then we need to divide by factorial(3) since otherwise we are counting redundant case.
So note that the x^3 has been divided by factorial(3) which is 6.
Similarily for other letters. Try to understand that x^n denotes that the letter appears n times in the word. Now is it clear ???
 
 
Catalogs Discussion Forums -> Algebra -> permutation and combination -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Well yes there is one more method where u actually take case and see that whether we have taken all different letters or some letters are alike and so on.
 
However the method described above is simple as u do not need to worry about the cases. The answer will automatically come. DO you understand the approach that has been used above ??
Catalogs Discussion Forums -> Algebra -> permutation and combination -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Great work done this a absolutely correct approach !!!!!!!!!!
 
I hope ruhi this helps u !!
Catalogs Discussion Forums -> Thermal Physics -> conic 3-d flow of heat -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
See, in a cone the area of the disc at any distance from the top is varying and also the rate is varying. So the integral is not a two dimensional integration. And thus the  book says that the integration cannot be done. Now for the cylindrical flow the area is not varying it is a constant that is the face area of the cylinder. Ok?? Thus it is written as A.

Now good book for thermal physics, I always will make one comment use H.C Verma. It is the best book. Right ???

Take things easy and try to solve some easy questions so that it make your concepts strong before going for hard problems. Okay.

cheers
 
 
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