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the word's...GARDEN

vovels are....E and A only...

now , put A as the first word....so..no of arrangements...5!

put it as 2nd word....now we have...4 choices to put E..and arrange other words in...4*4! ways..

now put it as 3rd word...now we have..3 choices to put E...and total choices=3*4!

......similarly we have...2*4! and..1*4!....

so answer....5! + 4*4! +3*4! + 2*4! + 1*4! =360 ways

hope it helps...cheero :)

is the answer 0 ?

q1---

fraction of molecules of reactants having energy equal to or greater than activation energy= e^(-E/RT)

put the values n get the answer

q3---

k=Ae^(-E/RT)

k=2.418 * 10^-5

E=179.9 kJ/mol

T=546 K

R=0.0821

now put these values and get the value of A

hope it helps...

"it SUCKED"

as it's a metal plate(conductor)....and it touches those edges...so.....net charge now on capacitor is 0

so it's no more a capacitor now.....so capacity becomes infinite

increases activation energy or decreases frequency factor

as

f(x+y)=f(x).f(y)

f(x) is of the form a^x

f'(0)=2

f'(x)=(a^x)ln(a)

f'(0)=ln(a)=2

a=e^2

so...f(x)=e^(2x)

hope it helps....cheero :)

some more replies plz

i think it's (c)......R/L seconds

i live in haryana............i culd'nt find that in the list

i just wanted to know.......HOW TO APPLY FOR RMO ( REGIONAL MATHEMATICS OLYMPIAD ).......????....and any other info that u have about it..... :) ......plz help...rates assurreedddd..........

write cosx + cos3x = 2cos(2x)cos(x)

it becomes....

cos(2x) + 2cos(2x)cos(x)=cos(2x)[1+2cos(x)]=1/4

cos(2x)[1+2cos(x)]=cos(2x)sin^2(x)=1/8

(1-2sin^2x)sin^2x=1/8

sin^2x - 2sin^4x = 1/8

let sin^2x=t

t-2t^2=1/8

8t-16t^2=1.....solve this eqn for t..u get....t=1/4...now frame the general solution :)

|dv/dt| not equal to 0.....this represents....maginitude of acceleration is finite....means there is some acceleration, wat so ever.......

and d|v|/dt....represents......rate of change of speed......

now consider a uniform circular motion...velocity is changing everytime coz direction of velocity is changing.......

so |dv/dt| is non zero

but rate of change of speed(magnitude of velocity) is 0

so d|v|/dt=0

hope it helps...chhero :)

well, lemme ask you...how wud a charge know of presence of another charge ???......

every charge sets up an electric field to know the presence of other chages so that they can interact with each other...

.....a quantity that does not depend on magnitude of the charge wud help making problems simpler than ever....and that's what hidden behind this concept....

hope it helps...cheero :)

*edited.....THANKS ganesha1991

d=A+D/C^2

d is a constant having dimensions of L^2

so,...D/C^2 should also have dimensions of L^2....so C^2 gets the dimensions of M L^(-5)...C has dimensions of M^(1/2) L^(-5/2)

hope it helps...cheero :)