Messages posted by srini

Thank you sir for pointing at my mistake:)

thank you akarshita shangi124 memoman debotash.babai ashwin18 royvivek1992...it takes effort to read but more effort to implement....whatb is imporatnt is not just reading...learn from it..
smart are those who learn from their mistakes...smater are those who learn from other's mistake:)

thanks for reading..

I don't know why i am writing this.I don't know if i am worth advising but still i felt i should write and hence i am writing(probably because goiit helped me more than you can expect)...iit is only few months away..i can see so many sites which say so and so days left..blah n blah

First of i want to tell you one thing..please don't study just to get into iit...as in don't over work yourself solving 100 books or so on(remember there is still the 101 th book left always)...keep your concepts clear when i say this i mean that whenever you solve a problem try finding the concepts involved..make a note of the things you feel are important and re-read them every few days..moreover the day before exam you may feel you don't know anything ..it was a total black out for me...at that time when you open a solomon or arihant it won't work ....it will only turn worse...that time when you read this book of yours..now since it is in your hand writing and you are familiar with it ...you will feel confident..Now is the time you know all the concepts but your brain needs to organize and channelize your thoughts and concepts..btw...remember whenever you study study effectively...it counts...

next,most important thing...for heaven's sake DON'TGET EXCITED OR ANXIOUS ABOUT THE PAPER...keep cool...i remember my hands shaking before the exam( to be very honest i never get tensed during exams..no matter how much i have studied...even 1 out of 10 chapters..lol)...but during this exam i got tensed...and i think this is one factor which adds...and how to avoid it..just tell yourself to keep calm...think of good movies(lol)...just say yourself this is another exam that's it...it is no going t change your life entirely

and anoher thing...remember this...all that you studied and worked for will NEVER go waste...whether you get iit or not

So good luck

please comment and tell if i have to edit anything:)

where is the ques?

When we say a wave equation it has to satisfy certain rules(i don't remember all.. )

A wave is of the form

here it doesn't satisfy

d²y/dx² =2

1/v² d²y/dt²=-2/v

Therefore,it is not a wave equation

From Lagrange's Mean Value Theorem,

there exist some cE(a,b) such that f'(c)=[f(b)-f(a)]/[b-a]

here

f'(c)=1

now if f'(c) is atleast a quadratic expression with D>0(unequal roots)

Then there exist two c's or c1 and c2 for which f'(x)=1

That is,

f'(c1)+f'(c2)=2

let the equation be f(x)= ax³+bx²+cx+d..

Give f(-1)=10=> -a+b-c+d=10

f(1)=-6=>a+b+c+d=-6 =>b+d=2

a+c=-8

also maxima of f(x) at x=-1

=>f'(-1)=0( f('x)=3ax²+2bx+c) or 3a-2b+c=0

and minima of f'(x) at x=1

=>f"(1)=0(f"(x)=6ax+2b) or 6a+2b=0 or b=-3a =>a=1,b=-3,c=-9 and d=5

hence substitute and find

if you want i can work that too:)

To prevent further hydrogenation?

<= |x|+|y| (sides of a triangle)

=>k<=1 and k>0

k(0,1]

hope you understood the solution:)

didn't work out well when i tried(two times) in latex sorry:(

Bring to the form of (1+y/x)^a+(1+x/y)^b=1

differentiate

you get

ay(xy'-y)+bx(y-xy')=0=>y'(axy-bx²)-ay²+bxy=0

y'=y(ay-bx)/[x(ay-bx)]

y'=y/x

y²=ax³+b

tangent: 2yy'=3ax²

y'=2a at (2,3)

2a=4

a=2

y²=ax³+b

=>b=-7

7a+2b

7*2+2*(-7)

14+(-14)

=14-14

=0.

1.67492729(28)×10⁻²⁷ kg

SOURCE:Internet

Area=1/2*d1*d2

d1=24=>d2=18...

the diagonald bisect each other at right angles...so find'a'(side)with pythagoras theorem...

a=15

perimeter=4*a(since in rhombus all sides are equal)

perimeter=60 cm.

6.Draw the fbd...

horizontal forces N_X, ma

vertical forces NY ,mg

equating...

@@rajatsen91:i guess you should be subtracting one from the expression because one way includes choosing none of the sets which isn't true.

int c=1;

for(int i=1;i<n;i++)

{for(int j=1;j<=i;j++)

{cout<<c;

if(c==0);

c=1;

else

c=0;

}

log(xy)=log(x+y)

=>xy=x+y

y(x-1)=x => y=x/

x-1

There must be a condition on "a" that a>0,anot equal to1

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