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=cot^{-1}\left%20(\frac{x(x+1)+1)}{x+1-x}%20\right%20)=cot^{-1}(x+1)-cot^{-1}x)
Now use by parts for arccot : \left%20(%20\frac{d}{dx}cot^{-1}x%20\right%20)dx)
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dx=(x+1)cot^{-1}(x+1)+\frac{1}{2}log((x+1)^2+1))
Subtract these two to get the final answer
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The properties of individual elements and when they combine to form compounds are totally different.
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+%20b^{2}sin^{2}x) sin^{2}x)
If a^2 > b^2 then maximum value occurs at sinx=0 which is a^2 and minimum value occurs at sinx=1 which is b^2. Similarly for b^2 > a^2, max. value is b^2 and min. value is a^2 Therefore maximum value = max(a^2,b^2) and minimum value = min(a^2,b^2)
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We know derivative of |x| is |x|/x Let y = sinx-cosx then f(x) = |y| )
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Derivative of a function represent the slope of the curve at any given point, while integral represent the area under the curve.
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A theorem describing how the conditional probability of each of a set of possible causes, given an observed outcome, can be computed from knowledge of the probability of each cause and of the conditional probability of the outcome, given each cause.
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I suggest you to go for GIIT JEE Chandigarh Limited.
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For a triangle, a circle that lies outside of the triangle and is tangent to one side of the triangle and to the extensions of the other two sides. Also known as excircle.
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Circles are : and  Common chord is S1-S2 = 0 => which is to be compared with 4x-3y-24=0 }{4}=\frac{(\frac{b}{2}-2)}{-3}=\frac{-4}{-24})

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Emissivity, or "emissive power" [E(b)], is the rate at which radiant energy is given off by a body per unit area per unit time (often in W/m^2). Emittance (epsilon), on the other hand. is a dimensionless ratio ? the ratio E:E(b) ? that is, the ratio of the emissivity of a body to the emissivity of a perfectly-emitting and absorbing (theoritical) black body. Thus, emittances are always less than 1.0
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Check your work. No one is perfect; we all sometimes make simple mistakes. These simple mistakes can be enough to lower your grade or keep you from achieving your goal. Work the example problems in the book. Write the problem down and work it without looking at the steps or answer in the book, if you can. If you have difficulty, review the example in the book. This will force you to think through the concepts.
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Most of the times these predictions go wrong. When I was giving JEE-2005 people thought physics will be the toughest but it was easiest among three. Treat PCM as your children and treat them equally. If one comes hard it'll be for all.
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Let a = 4^(1/5) & b = 7^(1/10) Clearly a^5, a^10,..... & b^10, b^20,.... are rational Expansion of (a+b)^45 consists of 46 terms out of which a^5.b^40 , a^15.b^30 , a^25.b^20 , a^35.b^10 , a^45 are the terms (written without coefficients) which are rational. so in all 41 terms are irrational
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if you are asking about these institutes then yes vit srm are good institutes.
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Yes it is possible to produce current from sound using a transducer .A microphone is the most common example of that microphone is a transducer that converts acoustical waves into electrical signals. A condenser microphone, operates on a capacitive design. The cartridge from the condenser microphone uses basic transduction principles and will transform the sound pressure to capacitance variations, which are then converted to an electrical voltage. This is accomplished by taking a small thin diaphragm and stretching it a small distance away from a stationary metal plate, called a “backplate.” A voltage is applied to the backplate to form a capacitor. In the presence of oscillating pressure, the diaphragm will move, which changes the gap between the diaphragm and the backplate. This produces an oscillating voltage from the capacitor, proportional to the original pressure oscillation.
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SCRA: Special Class Railway Apprentices.
The approximate number of vacancies to be filled on the results of the examination is 42 out of it 4 vacancies are reserved for physically challenged candidates. The selection is made through UPSC
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In Vizag I would prefer Sri Chaitanya.
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My vote goes to NIT Jalandhar.
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Go through NCERT, all the basic things are written in good detail. After then read H C verma and solve problems from it.
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I agree with rahul. - or + sign is to show the polarity. Induced emf is -ve as it opposes the reason causing it.
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