Messages posted by priyesh

previous 255, now 265

maybe the question which is wrong & thus not attempted is given 3 marks

mine has increased by 10 marks

go for bits goa

f(x) = x^2- 2kx + k^2 + k - 5

since roots r real

=> 20 - 4k >= 0

=>k<= 5 ------------------------------------------------1

also f(5)>0

=> k^2 - 9k + 20 > 0

=> k<4 & k> 5 --------------------------------------2

from 1 & 2

k < 4

*edited*

message got posted 3 times due to some network error ,

* edited *

@akshaytalwar2

Dont post without having complete knowledge.

For ur kind info juit(jaypee solan) is a ugc recognized UNIVERSITY whereas jiit Noida is a Deemed university.

Jaypee solan is full fledged university , so please refrain from posting WRONG info about institutions on the net

I hope u understood Mr. Akshaytalwar2 :)

great!!!!!!!!!!!!!!!!!!!!!!
take it if u get it

try in amity or else take a seat via capitation fees in bvp or some other similar colleges who give admission via donation/capitation

@akshaytalwar

it is needed for counselling of jaypee, then what is the alternatve if we dont receive it till 25th

according to me ur on the borderline

I havent received my aieee rank card , i'm from delhi . Please tell if u all have received it or not.

ure cutoffs r not correct. It's way too high

then its a problem!!!!!!!!!!!!!!!!

dis is shocking!!!!!!!!!!

if its a deemed university(which i think it is most probably not sure though) then it does not require aicte approval only UGC approval is needed

many will drop out just wait and dont get disheartened

total no. of rectangles (including squares) are

9C2 * 9C2 = 1296

both are equally good, choose the one which is nearer to ur home

U will get ece in Noida comfortably

@ INR 1,995/-