Messages posted by sunshineson

ionic product of water is 1x10-¹⁴ at 25 degree C. What will be ionic product at 90 degrees?

Ionic product of water

but what are points C and D on the potentiometer? u took ressitance CD as the resistance of wire right?

there is difference between two figures

ie, in fig 1 defekction in G1= zero, because it is the balancing point. But in 2nd fig, how can u say that balancing point is on CD? ull figure will be modified for zero deflection, the portion CB will become C'B where C' is a point in between C and D

(x -2)5= 2(x+10)

5x-10= 2x+ 20

3x=30

x=10

he means can he concentrate on IIT coaching by taking computer science at +1 and +2 level.

frequency= 1/T = speed/distance

but speed v = nh/2pimR

and distance =2piR

therefore frequency = nh/4 pi² m r² calculate radius of frist orbit= 10^-15 m.

substitute in frequency formula. u get the answer

dont be so rude aditya.. u too might have done such things when u were new to this site..at least that is not a crap post. he has tried to answer to some query but at the wrong place.

im nt sure but let me try

angular momentum mvr = nh/2pi

but h= E/v and E is inversely proportional to n² which means inversely proportinal to radius r also (r prop. to n²)

this means ang. momentum = nE/2 pi v means it is directly proportional to n and E.

or it is driectly proportional to n and 1/r (beacause E proportional to 1/r)

but n is proportional to r^1/2 which means angular momentum is proportional to r ^-1/2 (from above two lines)

Nice..i hope even for AIEEE this will help..i hope shashank will come up wid articles involving increasing,decreasing order(acidic,basic, etc)

In first six throws and last four throws.. there can be these many cases:

0 ,1,2,3,4 heads. Not more than that.

Use this formula ⁿC_rP^rQ^(n-r)

where P=1/2 Q=1/2 n=10 and substitiute r=0,1,2,3,4 and add them together.

nice.

I gave aieee in 2009. i am attempting again in 2010. if u want to crack n first attempt..read only topics covered in ncert books. NOT NECESSARY that it is from aieee brochure only. cos ncert u can know imp. topics. and also solve 3 hr full model papers at least 10 times from february and analyse ur performance

Yes..this is because as size increases, an atom becomes less proton donor, but more proton acceptor, hence basic char. increases

yeah..remember that acidic character increases in a period on account of small size..this means basic character increases down a group.

basic character increases as we go down the group.

aieee or iit??

iit- go to iit website and select ur zone-enter yur application no.

aieee. visit www.aieee.nic.in

nice omkar

For that u should prove that b/c+a is the harmonic mean of a/b+c and c/a+b.

now 2 (ac/(a+b)(b+c))/a^a+ab+bc+c^2

solve the above and prove that it quals b/c+a

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