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I'll suggest , instead of rememebering the formulas directly, u derive it first n then memorise it...... it will help, or give a problem here, n i'll show u how to solve it!
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I think the above is right.... most of the inequalities are solved using AM > GM >HM concept.
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manini, the answer shud be 2qe/K if the above mentioned concept is not applied and if it is applied it will be 4qe/k. Lets wait for the answer frm the experts...
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experts, i hav a doubt, the extension in case of sudden loading is always twice of the extension in case of normal/gradual loading. shudnt that concept be applied here???
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cant say exactly , it may be it may be not.... m in a doubt for that, cuz the intercept form of line is x/a + y/b =1, where a and b are the intercepts on x-axis and y-axis respectively, but x=y cant be expressed in this form!!! lets wait for any response frm the experts........
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well, i hav also seen the BMAT papers, they are very easy.... dnt take it otherwise but they r really quite easy, infact one of my frnds, score 170 and so marx in those tests... and jee is defintely going to be atleast higher than BMAT level....
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how to find the resistance of a 6X6 square wire mesh , across the diagonally opposite points, if its given that the resistance of each side of small square is R. PS: i want the shortest approach
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the answer given was x=y.... while solving x+y=4 shud be the only answer wat i meant to ask here is that are "zero intercepts justified".... i hav asked it frm experts also... see the following post
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Is zero intercept for a line defined???? suppose its given that a line passing thru a given point (a,a) and having equal intercepts on the axis, we hav to find its equation, then the answer is x+y=a. but wat i want to ask is, x=y also passes thru the point and its intercepts , which are zero are equal. is this justified??? i hav searched Loney also for this, thr also the concept of zero concept is given..... but dnt knw, if it can be used also or not!
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Thanx sir 
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so is my answer correct???
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Thank U Sir, Thanx Alooot
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really hats of to u dear.... i really wish to see ur name in the top AIRs of JEE-08..... keep working.... u'll defintely make it big!!
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4COS  +3SIN =3 its of the form a sin x + b cos x =c dividing both sides by sqr root (a2 + b2) , we hav it in the form of sin (y +x) = c/( sqr root (a2 + b2)) where sin y=b/( sqr root (a2 + b2)) and cos y=a/( sqr root (a2 + b2)) here y= 57 degree and it will be sin (57 + x) =3/5, hence x can be solved
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yupp, the above one is right!!!
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hey is all this in JEE sylabus..??????
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nothing can be said now.... most probably, it will be individual subject's cut-oof (paper1+2), n then cut-offs for paper1, paper2 and combined 1+ 2 .
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thanx
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thanx for those regards, but i'll be happier if u give me a "vote" for it  ... newayz, thats wat i was thinking too, but the answer given is 2qE/K. but i support wat u hav said!!
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