phenoxide ion is more reactive towards electrophilic attack because of the +R as well as +I effects of O^-.

the OH on phenol has +R but -I effects which lowers the -ve charge on the ring.

E.A.S. will take place at the ortho or para position depending on the stability of the product obtained.

in c++,it will be

#include<iostream.h>

#include<math.h>

void main()

{

int n,no=0;

cin>>n;

no=sqrt(n);

if(no%1==0)

cout<<"number is a perfect square";

else

cout<<"not a perfect square";

}

how can you say that f(x) is of degree 1

int 1/(1+sin x)

multiply and divide by (1 - sin x)

int (1 - sin x)/(1 - sin² x)

int [(1 - sin x)/cos² x]

int [sec²x - sec x tan x]

tan x -sec x +c

is it  ln(x)  - { [ ln|xⁿ+1| ] / n }                                                                                                                                                                                                                                                                                                                                                            

is it 2 [ sin(x) + xcos(A) ]

is the answer x² + y² - 2x - 4y - 20

not necessarily, usually the torque is calculated about the COM  but it can also be calculated about any point that is not accelerating.for accelerating points you have to consider the torque of the pseudo forces. 

this happens because the shadow is formed at some height above the surface of the earth.

if the plane flies very close to the surface,then its shadow can be seen.

 the umbra(dark region of the shadow) does not reach the surface when the plane is at a great height above the ground.

is it approx 76.5%

is the answer to the second part (4/3)v₀

use the property a^log_ax =x

eqn reduces to x²-4x+5=x-1

x²-5x+6=0

x={2,3}

is it 0.00435

ya, sorry abt that .i forgot that in cos you have to take the +- part in the general eqn.

is it 2 cos(2)