Let l,m,n be three consecutive natural numbers(l>m>n).If the angle A of the triangle ABC be given by
sin A=[(a2+b2+c2)(l2+m2+n2)] / (al + bm + cn)2
and the perimeter of the triangle is 12 units,then the area of the triangle ABC is
(Here a=side opp to angle A.......same goes for b and c)
b)6 c)15/2 d)none
If u guys can do it and show how u did it....rates assured....