Smile, an everlasting smile
A smile can bring you near to me
Don't ever let me find you wrong
Cause that would bring a tear to me
This world has lost it's glory
Lets start a brand new story
Now my love

 

You think that I don't even mean
A single word I say...
It's only words
And words are all I have
To take your heart away

Talk, in everlasting words
And dedicate them all, to me
And I will give you all my life
I'm here if you should call to me
You think that I don't even mean
A single word I say...

[CHORUS, repeat]

Da da da da da da da
Da da da da da da da da
Da da da da da da da da

Da da da da da da da da

This world has lost it's glory
Let's start a brand new story
Now, my love
You think that I don't even mean
a single word I say...

[repeat CHORUS twice]

Dude .....

Check the first question .....

Both the lines 3x - 4y = 0 and 12x - 5y = 0 intersect at origin .....

(How come it may be a rhombus ..... )

Well .....

Relative velocity of a particle (say B) w.r.t another particla (say A) is nothing but the velocity of B as seen by A .....

 

Mathematically,

V_B/A = V_B/ground - V_A/ground

The same is for relative acceleration and relative displacement .....

a_B/A = a_B/ground - a_A/ground

S_B/A = S_B/ground - S_A/ground

 

Just apply these formulae whenever ya require .....

This much is enough to solve any problem regarding relative motion .....

 

Hope ya find it useful .....

For Maths ..... try M.L.Khanna

(The questions might be lengthy and repetitive ...... but its good for theory)

 

Inorganic chem ..... NCERT & O.P.Tandon

Physical chem ..... R.K.Gupta (Arihant)

..... (For problems see R.K.Mukherjee)

Organic chem ..... Morrison & Boyd (but study only whatever is in the syllabus)

 

Hope ya find it useful .....

Let the angle of incline be , the vertical height h and the hypotnuse l.

Thus, (h/l) = sin

 

For motion 1, l = (1/2)(g.sin )(t)

For motion 2, h = (1/2)(g)(t/2)

 

Dividing 2 by 1,

(h/l) = (1 / (2.sin) )

i.e. sin = (1 / (2.sin) )

 

Thus,  = sin^-1( 1/ 2 )

Well, I think there will not be any particular (i.e. standard) direction of that car.

 

Let i and j be the unit vectors along E-N direction.

 

Say, vel of A = ai + bj ;

       vel of B = mi + nj ;

       vel of car = xi + yj

Now, A and B are moving in same direction and vel of B is twice that of A .....

i.e. m = 2a and n = 2b ..... as the direction remains same

 

Now v_car/man = v_car/ground - v_man/ground

Thus for A: ( )i + 0j = (x-a)i + (y-b)j ..... i.e. y = b

Thus for B: 0i + ( )j = (x-m)i + (y-n)j ..... i.e. x = m

I've left the spaces blank .... as we know only the directions of relative motion ....

 

Thus, vel of car = mi + bj = 2ai + bj

And dir is tan^-1(b/2a) .....

 

 

Let me know if I'm wrong ....