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Catalogs Discussion Forums -> Mechanics -> Work Energy Power-LOTS question(Karthik2007 please reply) -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
15 replies   
I just want a relation between the given numbers and how did you get that relation?
Community shelf Community shelf -> GURU MANTRAS for Periodic Table -> Go to message
This Post 119 points    (21 Olaaa!! Perrrfect answer.   in 28 votes )   [?]
24 replies   
Group 1-
Read as- Hi Leena Ki Ruby Saas France mai
Elements- H  Li    K   Rb    Cs    Fr
 
Group 2-
Read as-     Beta maange car scooter baap raaaji
Elements-Be      Mg      Ca   Sr         Ba   Ra
 
Group 13-
Read as-         Baal   gain  tel(oil)
Elements-B  Al  Ga In  Tl
.
Group 15-
Read as-     Nana   Patekar  Asrani Sab bhikhari
Elements-N         P           As        Sb  Bi
 
Group 16-
Read as-        Usse      Teepo
Elements-Os S Se   Te Po
 
Group 17-
Read as-   Foote kulharh baraat aayi Eta
Elements-  F      Cl        Br         I    At
 
Group 18-
Read as-     Hey  Ney  Ar Kar Xenon Radon
Elements-    He   Ne   Ar  Kr   Xe      Rn
 
Period 2-
Read as-  Li   Be   Bak   Nauf 
Elements- Li  Be   B C   N O F
 
Period 3-
Read as-   Naamag Aalsi Pascal
Elements-  Na   Mg  Al Si P S Cl
 
Atomic no. 17-34
Cilca Secti(rhymes with Shilpa Shetty) V.C.R. man fee coni cuzan gagee assee
Cl Ca Sc Ti                                         V Cr    Mn   Fe Co Ni Cu Zn Ga Ge As Se
 
D-block-second row(Z=39 to 48)
Yeh Zar Nabmo Tak ru reh Padag Cad
Y     Zr   Nb  Mo Tc  Ru Rh Pd Ag  Cd
 
D-block-third row(Z=57 to 80)
Laa Hafta Warna reh us Irpatayu hag 
La   Hf Ta W        Re Os Ir  Pt Au Hg
 
Hey guys this is ur whole periodic table(except f-block). Isse shayad aapko compounds atomic no se yaad na ho but after learning these GURU MANTRAS you will be able to draw whole periodic table anywhere within 2-2.5 min.
 
Don't think ki ab yeh sentences bhi ratne padenge. What you have to do is just read these sentences aloud and look at ur periodic table and analyse how they rhyme with the elements of the table. Repeat just for 2-3 days and periodic table is on ur finger tips. And in any exam, like boards etc you can draw ur own periodic table on question paper within 2-2.5 min and this will help you very much in chapters in which you have to compare elements on the basis of their relative position in periodic table.
It has helped me a lot, so socha thodi help aa logon ki bhi kar doon.
 
It is self written and GURU MANTRAS also self made.
Please leave ur comments on how did you like them and RATE ME.
 
Catalogs Discussion Forums -> Mechanics -> Work Energy Power-LOTS question(Karthik2007 please reply) -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
15 replies   
Someone reply.
Catalogs Discussion Forums -> Analytical Geometry -> Challenging question of parabola -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
12 replies   
Yaar please koi try to karo.
Its a good question. Seems to be a bit difficult but certainly its solvable. Mujhe to 3 days se kuch strike kar nahi raha what to apply in this question.
Certainly applying distance formula is not the way to do it as it will be about 4 pages long as we don't know a relation b/w t1,t2.
Catalogs Discussion Forums -> Games, Puzzles and Quizzes -> prove that 18! is divisible by 23 -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
17 replies   
On dividing 18! from 23 we get, 278364074162086.95652173913043478.

So its divisible.
Hahahaha
Catalogs Discussion Forums -> Analytical Geometry -> Parabola -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
4 replies   
Equation of tangent is y=mx+a/m
here a=2, m=1.
For a tangent perpendicular to this tangent, m=-1.
Therefore equation of the second tangent is y=-x-2.
Solving the equations of both the tangents, you get (-2,0)

Rate me if satisfied.
Tell me if not understood.
Catalogs Discussion Forums -> Analytical Geometry -> Parabola -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
4 replies   
Answer is (-2,0)
Community shelf Community shelf -> THESE FORMULAE MIGHT INCREASE UR. PERCENTILE IN COMPETITIONS BY 1% (ONLY!!!) -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
9 replies   
You said that-If any parallelogram can be inscribed in a circle , it must be a rectangle
But square can also be incsribed in a circle and its a parellelogram too.
Catalogs Discussion Forums -> Analytical Geometry -> Challenging question of parabola -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
12 replies   
Prove that for a suitable point K on the axis of the parabola, the chord PQ through K can be drawn such that 1/PK2 + 1/QKis the same for all positions of P.
 
Salutes assured.
Catalogs Discussion Forums -> Algebra -> i need a solution for this -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
2 replies   
Is the answer 1000?
U can do this by assuming U have a total of 10000 basis points whose 1%=100 basis points.
Then ur answer will be 7550-6550=1000
Catalogs Discussion Forums -> Analytical Geometry -> conic section -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
1 replies   
conic section kya?
What's the question?
Catalogs Discussion Forums -> Mechanics -> Work Energy Power-LOTS question(Karthik2007 please reply) -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
15 replies   
Guys I have made the figure correctly.
This was a question in Locus Online test series.

Karthik, can you please explain yourself more clearly? By wrting the sum and telling how to reach that result?
Catalogs Discussion Forums -> Analytical Geometry -> find the perimeter -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
4 replies   
Abe kiska perimeter?
Catalogs Discussion Forums -> Analytical Geometry -> Straight Line Doubt -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
7 replies   
Its easy,
if these 3 lines are concurrent, then the relation between the coefficients is given by
Det |a1 b1 c| = 0
       |a2 b2 c|
       |a3 b3 c|
Take c common and it goes to RHS to become zero, we get
|a1 b1 1| = 0
|a2 b2 1|
|a3 b3 1|
This is the condition for collinearity of 3 points (a1,b1), (a2,b2) and (a3,b3).

Rate me if understood.
If not understood, tell me. I will explain again.
Catalogs Discussion Forums -> Mechanics -> Work Energy Power-LOTS question(Karthik2007 please reply) -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
15 replies   
A system comprising two blocks is shown, one of which is on an inclined plane. The pully is of negligible mass and is frictionless. The system starts from rest at position 1 and accelerates. Measurements are taken when the blocks reach position 2 indicate that-
(1) the KE of block A has changed by 330 J
(2) the PE of block A has changed by 588 J
(3) the KE of block B has changed by 110 J
(4) the PE of block B has changed by 98 J
 
The amount of mechanical energy that has been converted to heat because of friction is
A-12J
B-50J
C-258J
D-710J
 
The answer is 50J. Please explain how did it come?
 
Rates assured.
 
 
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