goIIT: IIT JEE AIEEE CET WBJEE VITJEE BITSAT IIIT AICET Engineering Entrance Experts, Student Discussion Community, IIT JEE Preparation Online

a formulAE IS NOT GOING TO apply there u have to start from the basics as ratio for atm radii in cases of isotopes the one having the more no of nucleons will have the larger radii and in case of same comp but diff E confi as cuin d9 and d10 the confi which is more stable will have the larger radii
if for any further confusions mail me gagar.iitk@gmail.com

if magnetic moment is given u only can find is a no of unpaired electrons by formulae or just take the max integer then u try for the E-configuration
here no option is going to be correct unless one finds a comp in which fe remains in +4 transition state

In case of compounds having more than one double bond, trans-cis and cis-trans are two different isomers when the double bonds are dissimilarly substituted. ..................yes i agree with this .....................but if the positions are dissimilar in this case cis-trans and trans-cis are going to be same here but here these are going to be OPTICAL ISOMER as the central carbon atom will become chiral if one double bond positioned itself in cis and another in trans but the no of geometrical isomers for this compound is 2 and no of stereo isomer 4

*********************Deleted for unacceptable language**********************

IGOT TO TELL U THAT STEREO ISOMERS ARE'NT THOSE KNOWN AS GEOMETRICAL ONE ONLY ......FIRST MISTAKE SECOND .............NUMBER OF GEOMETRICAL ISOMER DOES'NT MATCH AT ALL AS ........CIS-TRANS =TRANS-CIS (IF I AM TACKING ABOUT GEOMETRICAL ONES) EBE

*********Admin: Deleted for unacceptable language. any further such actions will have the account locked. Please note that while communications, basic courtesy is paramount.*********

total no of stereoisomers possible for

CH(Cl)==C(Cl)---CH(Cl)----- C(Cl)==CH(Cl)

and plz with full explanation

thats true that these things not included in jee course but it is advisable to have a slight idea of these topics because u have to apply the concepts in other question which are very well included in your course ...........

with the help of VSEPR theory we can give the expected ans not the exact one as there limitations of this theory one has to be very flexible in the approach

to smrity mathur mam plz check the basics of quantum no's so that u will be able to understand the ans
1s2 2s2 3s2 4s2 3p6 5s2 4p6 6s2 5p6

better you go for ATKINS

if i redifine the quantum no's as

n=1,2,3..............infinity

L= 0,1,2,3.........n (but taking only odd values)

m= -L,-(L-1)............0,............L {taking only even values (moduluswise)}

S= -1/2,1/2

what should be the electronic configuration of Zn(30)

order is
chlorobenzene
there indeed a problem with the system

There is a prob with the sys whenever i am placing thetached to the second corbon atom CH3 group to the second corbon atom the sys rearrangaes to the first one plz read the ans as CH3 attached to the second carbon atom

CH3--CH--CH=CH--CH3
I
CH3

ANS:

CH3--CH--CH=CH--CH3
I
CH3

for the ans of this Q u have to check the reactivity of the ring towards the electrophyllic attack as this rxn uses nitronium ion as the attacking reagent cl is a de-activator methoxy is activating the ring by +m effect and methyl is by +I effect benzene remains the same so the order is chlorobenzene