i agree that the volume increases but the bob will not creak out this is because the friction between the ice and the wall of the bob doest not allow to form it solid so the bob does not crack open

it measures weigth of the body and not mass

  the weighing machine in a lift shows the loss or gain of weight when in motion with accleration other than g, real weigth on earth when at rest adn zero weight when accleration is equal to g

 

as it is a pendulum the time period is 2^{[ ]}l/g so it doesnt depend on the mass of the bob

if it is a time period of a loaded spring then mass comes into consideration

 

the ans is 2.45m. The ans is as follows

 

h=u^2/2g

  =70X70/2X10

 =245cm

 =2.45m

 

as they r linearly independent i, j,k, can be equated as follows

(mn+r)=0

(l+m)=0 &

(n+p)=0

hope it is clear for u

 

 

is the answer 0 if it is correct i will send u the procedure

if it is wrong give the answer please

rohanroy is correct but there is a small mistake in finding out S_n+1.

 

there (a/2)(2(n+1)-1) = (a/2)(2n+1) and not -1

 

now find out the ratio

 

In a triangle ABC meadians AD and BE are drawn. If AD=4, DAB=/6 and ABE=/3, then the area of the ABC is

1)16/3         2)32/3           3)64/3      4)8/3

 

 

please show with steps

 

the ans is 2)

please resolve the forces acting on the man in the dich

now u get fcos#,fsin#,fcos#,fsin#               (#----theta)

2fcos#=mg

f=mg/2cos#

as the man moves up cos# value decreases

let he is from heigth h from the ground

cos#=h/z

z= 

 

^{[ ]}h^2=(d/2)^2

f=mg/2(h/z)

f=mgz/2h

 =mg

^{[ ]}h^2+d^2/4

 

hiii twinkle......

i never knew the people copy from the other web sites for answering these questions. i never did so,i try for the answer if suppose i dont get it i wait till someone posts the answer

try to draw the free body diagram first then identify the forceses acting on them then it will become very very easy and ur problems will be running very smoothly

 

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