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yes CH3CH2OH undergoes mild oxidation during the process to form CH3CHO which has CH3C=O linkage and hence gives positive iodoform test
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see it this way
inf + 2 is also equal t o infinity
so infinity - infinity can be written as infinity - ( infinity + 2)
so it will be - 2 ... it can be any number this way.. got it ? :)
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neeral is correct and also infinity - infinity is not zero because we dont know the exact value of infinity... its just a concept of mathematics... infinty is a whole big branch of maths in itself its not just any simple number..
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s>0 ... n yes gud thinking rajatsen but it can be done the other way too by seeing that c >1 and b<-2 and then checking and finding that s > 0 always
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correct... jus make the discriminant greater than equal to 0
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iodoform test...
it will only be given by ethanol and not methanol
yellow ppt will be formed by ethanol
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this is such an easy question..
X E R ... all real values of x.
as when we solve, in the last step we get
2 ^(x+2) = 2 ^ (x+2)
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this is such an easy question..
X E R ... all real values of x.
as when we solve, in the last step we get
2 ^(x+2) = 2 ^ (x+2)
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anyway i think the answer is i/2 (iota / 2)
let .. root -1 - root -1 - root -1... upto infinity = y
then y = root -1 - y
2y = root - 1
y = i /2
*PLZ RATE*
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infinty is neither even nor odd...
rich_1986 i think ur question is wrong...
the one we CAN solve is where there are all + signs not - sign
and the under root sign is over all of them naa?
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Ans) 6 ( sin@cos@ - 1)
or
3 (sin2@ - 2)
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root of [ (62.5)^2 + ( 30 + 12.5 root3 ) ^2 ]
( i found total displacement along x axis and total displacement along y axis therefore magnintude of displacement is root of x sq + y sq.
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oh damn... i mixed up another question here... yup its 37.
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yes the 3rd method of aankur verma's is the easiest.. thts wht i use too
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2 sigma bonds + 0 lone pairs = sp
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