This Question can be solved by Simply comparing areas os the Independent triangles
Let ABC be an equilateral triangle and P be any point in the interior of it.
Let Pl , Pm and Pn perpendicular to the sides AB , BC and CA.
Now area of Triangle ABC =
[ ](
3)/4 a
2 = 25
[ ]
3
Now ar triangle PAB = 1/2 * base * ht
=10
and ar triangle PBC = 15
Therefore ar Triangle PAC = 25(
[ ]
3 - 1)
Hence 1/2 * 10 * Pn = 25(
[ ]
3 - 1)
hence Pn = 5(
[ ]
3 - 1)
hence my answer is 5(
[ ]
3 - 1)
Plzzzz Rate me. um new in this field