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im not clear wid the question....while solving how many biased coins do we have to consider 4 or 5?? or do u mean that their r either 4 or 5 coins in the bag???can u plz specify

see the distance of the image frm the mirror will be 60 cm... but if the distnace is to be calculated frm the observer thn we have to consider the refraction again....are we supposed to calculate that or is this the answer??

centre of mass is the point whr the whole mass of the body is supposed to be concentrated whereas centre of gravity is the point whr all the weight of the body is concentrated ....centre of mass coincides wid centre of gravity if body is lying in a uniform gravitational field...otherwise centre of gravity lies above centre of mass...
hope it helps u

hey kane many happy returns of the day!!!!
have a long long long ......life and may all ur wishes come true!!!!
god bless ya......have a blast

very nice!!!! keep it up

excellent work!!!! keep it up!!!

in a projectile motion if velocity makes @ angle wid the horizontal thn horizontal vel = v cos @ and vertical vel is v sin@...
vertical vel is zero onli at the highest point of the projectile motion
and yes vertical acc is always g...and unless something is given in the ques we assume the horizontal accelaration to be 0

see first find the velocity of centre of mass by using m1v1 + m2v2/m1+m2
...since they r moving towards each other velocities r in opp direction ...
therefore velocity of centre of mass will be 1x2 - 2x 1/
2+1
=0....since velocity of centre of mass is zero hence displacement will be 0.....nudge me if u hv any doubt

let A ( p^2, -p) B (q^2 , q) and C ( r^2 , -r) be the vertices of traingle ABC.

a parallelogram AFDE is drawn with D , E , F on the line segment BC, CA, AB respectively. using calculas show that the maximum area of such parallelogram is (p+q)(q+r)(p-r)/4...

plzz help rates assured...

the answer is 20 ml^2/3
find the moment of inertia due to one rod passing through its centre perpendicular to its axis ....
thn find it along the centre of mass of the system by using the perpendicular axis theorem....
and thn multiply it by 6 as thr r six such rods...
nudge me if u hv any doubts

a much better way to find range is to find the inverse of the function and then find the domain of the inverted func....as it is much easier to find the domain than the range directly...

u cant solve it unless and untill u hv 3 such equations...
if u hv 3 thn assume 1/x =u....1/y=v... 1/z =w
and solve using matrix method..u know it i suppose
if not nudge me

take both the terms separately...
sin x/cos^2x + cos x/ sin^2x
=now for the first part u take cos x = t
and thn for the second part u take sin x = t...
and in both cases u have their derivatives in trhe numerator...
i hope now u will be able to solve it
the answer will be
sec x - cosec x
rate me if it helps u

plzz check ur question ... i think its an inverse trigo ques...
ill answer it for sure...
instead of 1/ cos4/5
it wud be cos inverse 4/5 and similarly tan inverse 2/3 ...
if thats the case thn im getting 17/ 6 and ill tell u hw bt confirm it...
if its inverse thn first change cos inverse to tan inverse and apply the formula ull get the answer....

the mean kinetic energy of a particle of mass m with constant force in any interval of time will be......whr w1 and w2 are the initial and final velocities